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How many combinations can be formed from 6 bits?
26 = 64
What is the significance of 26 complement in binary arithmetic?
26 decimal is 11010 binary. Its ones complement (in 5 bits) is 00101, which is 5 decimal. In 16 bits, its ones complement is 1111111111100101 which is -27 when interpreted as a signed decimal, and 65509 as an unsigned decimal.
26 days equals how many days?
26
How many cents in a dollar if you had to find 26 percent?
26% of a dollar is 26 cents
How many times 6 go into 156?
Exactly 26 times
How many subnets can you have in a class C network with a 26 bit mask?
A Class C IP address has 24 bits for network and 8 bits for host. So to have a subnet mask of 26 bits, you will need to use 2 bits from host part.Number of subnets is given by the formula : 2^(no. of bits used from host part).Hence number of subnets in this case would be = 2^2 = 4.For e.g. if the class C IP address is 200.168.210.0the 4 subnet addresses would be :11001000.10101000.11010010.00000000 = 200.168.210.011001000.10101000.11010010.01000000 = 200.168.210.6411001000.10101000.11010010.10000000 = 200.168.210.12811001000.10101000.11010010.11000000 = 200.168.210.192Note: The digits in bold are the mask bits.
Divide 192.168.1.024 into 4 subnets?
I guess the network address is 192.168.1.0/24. This can be subnetted if we take two bits from host part to network part. 192.168.1.0/24 in binaries... 11000000.10101000.00000001.00000000 - IP Address 11111111.11111111.11111111.00000000 - Subnet Mask Take two bits from host part to network part 11000000.10101000.00000001.00 000000 - IP Address 11111111.11111111.11111111.11 000000 - Subnet Mask Now we get four networks... 1) 11000000.10101000.00000001.00 000000 - IP Address 11111111.11111111.11111111.11 000000 - Subnet Mask 192.168.1.0 - IP Address 255.255.255.192 - Subnet Mask 2) 11000000.10101000.00000001.01 000000 - IP Address 11111111.11111111.11111111.11 000000 - Subnet Mask 192.168.1.64 - IP Address 255.255.255.192 - Subnet Mask 3) 11000000.10101000.00000001.10 000000 - IP Address 11111111.11111111.11111111.11 000000 - Subnet Mask 192.168.1.128 - IP Address 255.255.255.192 - Subnet Mask 4) 11000000.10101000.00000001.11 000000 - IP Address 11111111.11111111.11111111.11 000000 - Subnet Mask 192.168.1.192 - IP Address 255.255.255.192 - Subnet Mask We get four networks and the networks are 1) 192.168.1.0/26 2) 192.168.1.64/26 3) 192.168.1.128/26 4) 192.168.1.192/26 Refer: http://www.omnisecu.com/tcpip/internet-layer-ip-subnetting-part1.htm
How many combinations can be formed from 6 bits?
26 = 64
Subnet mask of 255.255.255.192 Determine the prefix?
/26
When was Bits of Life created?
Bits of Life was created on 1921-09-26.
How many different values can be represented by 6 bits 7 bits 8 bits and 10 bits?
To find out how many different values can represented by a certain number of bits, we can use the following formula 2n-1 and that is because the first number is always a zero.Based on that 6 bits = 26- 1= 64-1=637 bits= 27-1= 1278 bits= 28-1=25510 bits= 210-1=1023# of bits1=12=33=74=155=316=637=1278=2559=51110=1023
Is 192.168.9.64 26 a valid network address for IPv4?
Yeah it is! Here is why You have the subnet mask of 26 bits. So its becomes 255.255.255.192. So the first three octets will be in the network address for sure. So we are done upto 192.168.9.x. In the last octet you have 2 bits on from the left, i.e. 128 64 32 16 8 4 2 1 1 1 0 0 0 0 0 0 You see that the bit corresponding to 64 is 1. That means it can come in the network address.:)
How many bits are used to represent a letter?
ASCII = 7 bit Unicode = 16 bits UTF-8 =8 bit
What is the significance of 26 complement in binary arithmetic?
26 decimal is 11010 binary. Its ones complement (in 5 bits) is 00101, which is 5 decimal. In 16 bits, its ones complement is 1111111111100101 which is -27 when interpreted as a signed decimal, and 65509 as an unsigned decimal.
Refer to the exhibit Which three ipv4 addresses represent a broadcast for a subnet?
172.16.4.63 /26172.16.4.191 /26172.16.4.95 /27172.16.4.63/26172.16.4.191/26172.16.4.95/27172.16.4.63 /26· 172.16.4.191 /26· 172.16.4.95 /27172.38.27.4 and 10.255.255.248172.16.128.154/18172.16.255.254/18172.24.64.254/18172.24.127.254/18**192.168.9.99/28**192.168.9.64/26**192.168.9.64/28
As a networking consultant you've been asked to help expand a clients tcpip network the network administrator tells you that the network id is subnetted as 1852754026 on this network how many bits of?
26
How many host can you have for 10.20.50.0 subnet mask 255.255.255.0?
253. Valid addresses would be from 10.20.50.1 to 10.20.50.254 10.20.50.0 is the network address. 10.20.50.255 is the network broadcast address. Any network with a subnet mask of 255.255.255.0 will support 253 hosts.
