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How many calories are required to raise the temperature of 105 grams of water from 30.0 degrees C to 70.0 degrees C?
q (amt of heat) = mass * specific heat * temp. differenceThe specific heat of water is 1.00 cal/goC & the temperature difference is 70-30 = 40oCq = (105 grams)*(1.00 cal/goC)*(40oC)= 4,200 calories
How much heat is necessary to change a 52.0 gram sample of water at 33.0 degrees Celsius into steam at 110 degrees celsius?
Raise the temp of 52 grams of water from 33.0 C to 100 C = 52*67*4.184 = 14.577 kJConvert evaporate 52 g of water to steam without change of temp = 52*2259 = 117.468 kJRaise the temp of 52 grams of steam from 100 C to 110 C = 52*10*2.02 = 1.051 kJTotal energy required = 133.095 kJ = 31,811 calories or 31.811 kCal.
How much heat energy is absorbed in 65 gram sample whose temperature changed from 45 to 80 degrees celsius?
That completely depends on the specific heat capacity of the substance of which the sample is composed, which you haven't identified. It will take a lot more heat energy to raise the temperature of 65 grams of water 35 degrees than it would take to do the same to 65 grams of iron or yogurt, e.g.
How many calories to heat 10 ml of water from 25 degrees to 35 degrees C?
100
A sample of water has a mass of 13 grams and volume of 13 milliters what is the density of water?
1 gm/ml
How many calories does it take to heat a 100.0 g sample of water from 24.5 degrees to 38.2 degrees?
1370 calories
If you have a liter of water at 50 degrees celsius sea level You heat the water so that you apply 100000 calories About how much of the water will boil Express your answer in grams?
To raise 1000 grams of water from 50 to 100 degrees requires 50 degrees x 1000 grams of heat, so the answer is 50,000 calories. Water at 100 degrees requires an additional 550 calories to convert 1 gram fully into steam. Therefore the remaining 50,000 calories can convert 50,000/550 grams into steam. So 90.9 grams become steam, and that's the answer.
If 75 grams of water at 30 degrees Celsius absorbs 900 calories what will be the new temperature?
105C
How many calories are needed to heat up 5 grams of water by 3 degrees Celsius?
(5)(3)= 15 calories. 1 calorie is the energy (heat) to raise 1 gram of water by 1 degree celsius, so 5 grams of water (3 degrees Celsius) = 15.
How many calories of heat would it take to raise the temperature of 256 grams of water from 20 degrees to 99 degrees?
A calorie is the amount of heat you need to raise the temperature of one gram of water by one degree Celsius. Assuming you are raising the temperature of the water from twenty degrees Celsius to ninety-nine degrees Celsius, it would take 20,000 calories. To calculate this, subtract 20 from 99. This is the amount of degrees you need to raise the temperature of the water by. Then multiply that number by 256, the amount of water in grams. You should get 20,244 calories. In significant digits, your answer should be 20,000 calories.
) The temperature of a sample of water changes from 10 and degC to 20 and degC when the water absorbs 100 calories of heat. What is the mass of the sample?
one calorie of heat is able to raise one gram of water one degree Celsius so 400 calories could raise 1g of water 400 degrees, so it would raise the 80g by(400/80) 5 degrees Celsius plus the initial temp of 10 degrees, the 80g of water would have a final temp of 15 degrees Celsius
How many joules are necessary to heat a sample of water with a mass of 46.0 grams from 0.0?
46 calories (or 192, 464 joules) for each Celsius degree.
The amount of dietary Calories in one hard-boiled egg could raise the temperature of?
1,000 grams of water by 75 degrees Celsius
How many moles of water molecules H2O are present in a 27 gram sample of water?
There are 1.5 moles of water molecules in a 27 gram sample of water. This is calculated by dividing the mass of the sample (27 grams) by the molar mass of water (18 grams/mol).
How many calories are required to raise the temperature of 105 grams of water from 30.0 degrees C to 70.0 degrees C?
q (amt of heat) = mass * specific heat * temp. differenceThe specific heat of water is 1.00 cal/goC & the temperature difference is 70-30 = 40oCq = (105 grams)*(1.00 cal/goC)*(40oC)= 4,200 calories
How many calories and carbohydrates are in the various types of onion and what is the the water content?
An average onion has 35 calories, 3 grams of carbohydrate, and is 92% water. An average red onion has 49 calories, 2.3 grams of carbohydrate, and is 90% water. A spring onion (scallion) has 23 calories, 2 grams of carbohydrate, and is 88% water.
How many calories in 100 grams of tuna?
100 grams of canned tuna in water has 116 calories, .82 grams of fat and 25.5 grams of protein. 100 grams of tuna in oil has 198 calories, 8.21 grams of fat and 29.13 grams of protein.
