It depends on how long would be the resulting string of character and if a character can be repeated or not
1) suppose a string of n characters and characters can be repeated
then for the first character one can choose 1 out of 26, the same for the second and so on then there are 26n solutions
2) suppose a string of n characters and none is repeated
This string would be less than 27 character long then n<27
for the first character one can choose 1 out of 26
for the second character one can choose 1 out of 25 (25 possible characters are left once the first is chosen)
for the third character one can choose 1 out of 24 (24 possible characters are left once the first and the second are chosen)
and so on
so there are 26x25x24x....x(26-n+1) solutions
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There are 26 characters in the English alphabet, plus 10 numerals. The total amount of combinations for 2 alphanumeric chars is given by (26+10)²=1296 If you also include capital letters then the result is (26+26+10)²=3844 Only letters gives 26²=676
26 million
The answer is 31C5 = 31!/[26!5!] = 169,911
To calculate the number of 5-number combinations from a pool of 1-26, we use the combination formula, which is nCr = n! / r!(n-r)!. In this case, n = 26 (numbers 1-26) and r = 5 (5-number combinations). Plugging these values into the formula, we get 26C5 = 26! / 5!(26-5)! = 26! / 5!21!. Simplifying this further, we get 2625242322 / 54321 = 65,780 different 5-number combinations.
Assuming you can have duplicate letters such as AAA, AAB etc... there are 26 x 26 x 26 combinations - which is a total of 17,576 permutations !