It depends on how long would be the resulting string of character and if a character can be repeated or not
1) suppose a string of n characters and characters can be repeated
then for the first character one can choose 1 out of 26, the same for the second and so on then there are 26n solutions
2) suppose a string of n characters and none is repeated
This string would be less than 27 character long then n<27
for the first character one can choose 1 out of 26
for the second character one can choose 1 out of 25 (25 possible characters are left once the first is chosen)
for the third character one can choose 1 out of 24 (24 possible characters are left once the first and the second are chosen)
and so on
so there are 26x25x24x....x(26-n+1) solutions
There are 26 characters in the English alphabet, plus 10 numerals. The total amount of combinations for 2 alphanumeric chars is given by (26+10)²=1296 If you also include capital letters then the result is (26+26+10)²=3844 Only letters gives 26²=676
26 million
The answer is 31C5 = 31!/[26!5!] = 169,911
To calculate the number of 5-number combinations from a pool of 1-26, we use the combination formula, which is nCr = n! / r!(n-r)!. In this case, n = 26 (numbers 1-26) and r = 5 (5-number combinations). Plugging these values into the formula, we get 26C5 = 26! / 5!(26-5)! = 26! / 5!21!. Simplifying this further, we get 2625242322 / 54321 = 65,780 different 5-number combinations.
Assuming you can have duplicate letters such as AAA, AAB etc... there are 26 x 26 x 26 combinations - which is a total of 17,576 permutations !
Assuming you are using the standard English alphabet, the number of combinations you can make are: 26 x 26 = 676 combinations.
There are 26 characters in the English alphabet, plus 10 numerals. The total amount of combinations for 2 alphanumeric chars is given by (26+10)²=1296 If you also include capital letters then the result is (26+26+10)²=3844 Only letters gives 26²=676
26 million
As there are 26 letters in the alphabet. You can calculate the number of combinations by multiplying 26x26x26, giving you the answer 17576.
The answer is 31C5 = 31!/[26!5!] = 169,911
You could make 10*10*10*26*26*26 combinations, or 17576000 combinations.
Oh, dude, there are like 26 letters in the alphabet, right? So, for each position in a 3-letter combination, you have 26 choices. That means you'd have 26 choices for the first letter, 26 for the second, and 26 for the third. So, the total number of 3-letter combinations would be 26 x 26 x 26, which is... math.
There are 26 alphabetic characters (a-z) and 10 numeric (0-9) which together form 36 alphanumeric characters. If you include capital letters, then you have 62 (36 + 26) alphanumeric characters. 62 * 62 * 62 = 238,328
With 26 letters and 10 numerical digits, you have 36 characters altogether. If characters may be repeated, then the total numnber of 3-character groups is (36)^3 = 46,656. If characters may not be repeated, then the number of groups is (36 x 35 x 34) = 42,840 .
To calculate the number of 5-number combinations from a pool of 1-26, we use the combination formula, which is nCr = n! / r!(n-r)!. In this case, n = 26 (numbers 1-26) and r = 5 (5-number combinations). Plugging these values into the formula, we get 26C5 = 26! / 5!(26-5)! = 26! / 5!21!. Simplifying this further, we get 2625242322 / 54321 = 65,780 different 5-number combinations.
The answer is 26C5 = 26*25*24*23*22/(5*4*3*2*1) = 65,780
In California, for example, the first digit of a standard plate is a number, followed by 3 letters, and then three numbers. There are 26 letters in the alphabet, so there are 26 raised to the 3rd power combinations, or 26 * 26 * 26, which is 17,576 possibilities just of the 3 letters.