Q: How many combinations can be made using 3 objects?

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20

The answer is 10C4 = 10*9*8*7/(4*3*2*1) = 210 ways.

32C3 = 4960

24

3 x 3 x 3 x 3 = 81 combinations

Related questions

20

The answer is 10C4 = 10*9*8*7/(4*3*2*1) = 210 ways.

120 combinations using each digit once per combination. There are 625 combinations if you can repeat the digits.

32C3 = 4960

24

3 x 3 x 3 x 3 = 81 combinations

It is: 9C7 = 36

66

10,000

15

two: 36 and 63

9