3 x 3 x 3 x 3 = 81 combinations
45
32C3 = 4960
10,000.
5040, assuming none of the digits are the same. (Assuming they're not, there's 5040 unique combinations you can make out of 7 digits).
9*9*9 = 729 using the digits 1 to 9 and 2*9 using 10 and another digit. 749 in all.
45
10
32C3 = 4960
120 combinations using each digit once per combination. There are 625 combinations if you can repeat the digits.
Not repeating, it is 7*6*5*4 which is 840 ways ---- There are 7 choices for each of four digits, right? 74 = 2401
10,000.
5040, assuming none of the digits are the same. (Assuming they're not, there's 5040 unique combinations you can make out of 7 digits).
9*9*9 = 729 using the digits 1 to 9 and 2*9 using 10 and another digit. 749 in all.
Oh, dude, you're hitting me with some math vibes here. So, if you have 6 digits to choose from to make a 4-digit combination, you can calculate that by using the formula for permutations: 6P4, which equals 360. So, like, you can make 360 different 4-digit combinations from those 6 digits. Math is wild, man.
If you allow digits to be repeated (for example, 222 or 992), then there are 9 x 9 x 9 = 729 combinations. If you do not allow digits to be repeated, then there are 9 x 8 x 7 = 504 combinations.
45 In combinations, the order of the digits does not matter so that 12 and 21 are considered the same.
262/2*102/2 = 67600/4 = 16900