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There are 74,974,368 combinations.
- There are 59C6 = 45,057,474 combinations with 6 different numbers.
- There are 59C5 = 5,006,386 combinations with 5 different numbers. One of these needs to be duplicated and the one to be duplicated can be chosen in one of 5 ways so there are 25,031,930 of these.
- There are 59C4 = 455,126 combinations with 4 different numbers. Either one of them appears three times or two are doubled. That can be done in 10 ways so there are 4,551,260 of these.
- There are 59C3 = 32,509 combinations with 3 different numbers. Either one of them appears 4 times, or one twice and another three times, or all three appear twice. That can be done in 10 ways so there are 325,090 of these.
- There are 59C2 = 1,711 combinations with 2 different numbers. Either one of them appears 5 times, or one twice and another four times, or both three times. That can be done in 5 ways so there are 8,555 of these.
- There are 59C1 = 59 combinations with just 1 number, repeated six times so there are 59 of these.
Add these together.
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If you create a password using 4 numbers 0 through 9 how many different combinations are there without using the same number twice?
This is a factorial problem. The first number can be any of ten digits, the second any of nine (because you can't repeat a digit), the third any of eight and the fourth any of the remaining 7 digits. 10x9x8x7=5040 combinations.
How many 4 digit combinations can be made from 6 digits?
Oh, dude, you're hitting me with some math vibes here. So, if you have 6 digits to choose from to make a 4-digit combination, you can calculate that by using the formula for permutations: 6P4, which equals 360. So, like, you can make 360 different 4-digit combinations from those 6 digits. Math is wild, man.
How many 6 number combinations using digits 1 2 3 4 5 6?
654321-100000= 554321 combinations
How many 5 digit numbers from 1 0 6 2 9 and 7 have digits whose product is equal to 4?
If you are not allowed to repeat the digits then the answer is clearly 0.If you are allowed to repeat digits then the only way you can possibly reach a product of 4 is by using a combination of 3 "1's" and 2 "2's". The possible combinations are therefore:22111212112112121112122111212112112112211121211122Thus there are 10 numbers which meet the criteria.
What 4 number combinations can you get by using numbers 0-9?
There are 10C4 = 10*9*8*7/(4*3*2*1) combinations of 4 digits that are all different. That is, 210 of them, and I have no inclination to list them.
Using 4 digits what is the total number of combinations for a 4 digit lock code?
If the digits can repeat, then there are 256 possible combinations. If they can't repeat, then there are 24 possibilities.
How many number combinations of the number 1 through 8 can there be using 4 digits?
Oh, dude, let me break it down for you. So, you've got 8 numbers to choose from for each digit, and you're picking 4 digits in total. That means you have 8 choices for the first digit, 8 choices for the second digit, 8 choices for the third digit, and 8 choices for the fourth digit. Multiply all those together and you get... well, I'll let you do the math.
How many possible 4 number combinations can you get using numbers 0-9?
0000-9999 (10x10x10x10 or 104) = 10,000 possible combinations allowing for repeated digits. If you are not able to repeat digits then it's 10 x 9 x 8 x 7 or 5,040 possible combinations without repeated digits.
What is the number of possible combinations using 7 digits?
128
How many 4 digit combinations can be made using numbers 1 2 3 4 6?
120 combinations using each digit once per combination. There are 625 combinations if you can repeat the digits.
If you create a password using 4 numbers 0 through 9 how many different combinations are there without using the same number twice?
This is a factorial problem. The first number can be any of ten digits, the second any of nine (because you can't repeat a digit), the third any of eight and the fourth any of the remaining 7 digits. 10x9x8x7=5040 combinations.
How many 4 digit combinations can be made from 6 digits?
Oh, dude, you're hitting me with some math vibes here. So, if you have 6 digits to choose from to make a 4-digit combination, you can calculate that by using the formula for permutations: 6P4, which equals 360. So, like, you can make 360 different 4-digit combinations from those 6 digits. Math is wild, man.
How many 4 number combinations using digits 1357 one and only once?
To calculate the number of 4-digit combinations using the digits 1, 3, 5, and 7 exactly once each, we can use the permutation formula. There are 4 choices for the first digit, 3 choices for the second digit, 2 choices for the third digit, and 1 choice for the fourth digit. Therefore, the total number of combinations is 4 x 3 x 2 x 1 = 24. So, there are 24 possible 4-digit combinations using the digits 1, 3, 5, and 7 exactly once each.
How many 9 number combinations using 0-9?
There are only 10 combinations. In each combination one of the 10 digits is left out.
How many 6 number combinations using digits 1 2 3 4 5 6?
654321-100000= 554321 combinations
How many combinations can you make using 30 digits and what are they?
Yuo can make only one combination of 30 digits using 30 digits.
How many 4 number combinations using the numbers 12345?
To calculate the number of 4-number combinations using the numbers 1, 2, 3, 4, and 5 without repetition, you can use the formula for permutations. Since order matters in a combination, you would use the formula for permutations, which is nPr = n! / (n - r)!. In this case, you would have 5 choices for the first number, 4 choices for the second number, 3 choices for the third number, and 2 choices for the fourth number. Therefore, the total number of 4-number combinations would be 5P4 = 5! / (5-4)! = 5 x 4 x 3 x 2 = 120 combinations.
