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There are 74,974,368 combinations.
- There are 59C6 = 45,057,474 combinations with 6 different numbers.
- There are 59C5 = 5,006,386 combinations with 5 different numbers. One of these needs to be duplicated and the one to be duplicated can be chosen in one of 5 ways so there are 25,031,930 of these.
- There are 59C4 = 455,126 combinations with 4 different numbers. Either one of them appears three times or two are doubled. That can be done in 10 ways so there are 4,551,260 of these.
- There are 59C3 = 32,509 combinations with 3 different numbers. Either one of them appears 4 times, or one twice and another three times, or all three appear twice. That can be done in 10 ways so there are 325,090 of these.
- There are 59C2 = 1,711 combinations with 2 different numbers. Either one of them appears 5 times, or one twice and another four times, or both three times. That can be done in 5 ways so there are 8,555 of these.
- There are 59C1 = 59 combinations with just 1 number, repeated six times so there are 59 of these.
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If you create a password using 4 numbers 0 through 9 how many different combinations are there without using the same number twice?
This is a factorial problem. The first number can be any of ten digits, the second any of nine (because you can't repeat a digit), the third any of eight and the fourth any of the remaining 7 digits. 10x9x8x7=5040 combinations.
How many 4 digit combinations can be made from 6 digits?
Oh, dude, you're hitting me with some math vibes here. So, if you have 6 digits to choose from to make a 4-digit combination, you can calculate that by using the formula for permutations: 6P4, which equals 360. So, like, you can make 360 different 4-digit combinations from those 6 digits. Math is wild, man.
How many 6 number combinations using digits 1 2 3 4 5 6?
654321-100000= 554321 combinations
How many 5 digit numbers from 1 0 6 2 9 and 7 have digits whose product is equal to 4?
If you are not allowed to repeat the digits then the answer is clearly 0.If you are allowed to repeat digits then the only way you can possibly reach a product of 4 is by using a combination of 3 "1's" and 2 "2's". The possible combinations are therefore:22111212112112121112122111212112112112211121211122Thus there are 10 numbers which meet the criteria.
What 4 number combinations can you get by using numbers 0-9?
There are 10C4 = 10*9*8*7/(4*3*2*1) combinations of 4 digits that are all different. That is, 210 of them, and I have no inclination to list them.
