420
There are 8C6 = 8*7/(2*1) = 28 combinations.
You need to specify how many characters, form the eight, are to be in the combinations. For example, there is only 1 combination of 8 characters.
In what sense? - i dont know, put them in a triangle, in a z-shape, a stright line, a "U" shape...
5 X 4 X 3 X 2 X 1 = 120
420
81
There are 8C6 = 8*7/(2*1) = 28 combinations.
You need to specify how many characters, form the eight, are to be in the combinations. For example, there is only 1 combination of 8 characters.
In what sense? - i dont know, put them in a triangle, in a z-shape, a stright line, a "U" shape...
5 X 4 X 3 X 2 X 1 = 120
There are eight possible combinations.
Using the eight digits, 1 - 8 ,-- There are 40,320 eight-digit permutations.-- There is 1 eight-digit combination.
twenty-eight (28)
One!
87400 combinations
There are 8!/[6!(8-6)!] = 8*7/2 = 28 - too many to list.