27
For the permutation the equation is (8!)/(5!) assuming there is no replacement. Which is 8*7*6 = 336 For combinations the equation is (8!)/((5!)(8-5)!) = (8!)/((5!)(3)!) = (8*7*6)/(6) = 56
To find the number of combinations of five numbers from a set of eight, you can use the combination formula ( C(n, k) = \frac{n!}{k!(n-k)!} ). In this case, ( n = 8 ) and ( k = 5 ). Thus, ( C(8, 5) = \frac{8!}{5!(8-5)!} = \frac{8!}{5!3!} = \frac{8 \times 7 \times 6}{3 \times 2 \times 1} = 56 ). Therefore, there are 56 possible combinations.
If you have 8 distinct numbers and want to create 8-digit combinations using each number exactly once, there are 8! (8 factorial) possible combinations. This is calculated as 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1, which equals 40,320. Therefore, you can make 40,320 unique 8-digit combinations with 8 distinct numbers.
it depends on which 8 numbers your talking about
There are 8*7/(2*1) = 28 combinations.
For the permutation the equation is (8!)/(5!) assuming there is no replacement. Which is 8*7*6 = 336 For combinations the equation is (8!)/((5!)(8-5)!) = (8!)/((5!)(3)!) = (8*7*6)/(6) = 56
3*5*8 = 120
41
5*6*7*8=1680
You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.
(8 x 7 x 6 x 5 x 4 x 3)/(6 x 5 x 4 x 3 x 2) = 28 combinations
To find the number of combinations of five numbers from a set of eight, you can use the combination formula ( C(n, k) = \frac{n!}{k!(n-k)!} ). In this case, ( n = 8 ) and ( k = 5 ). Thus, ( C(8, 5) = \frac{8!}{5!(8-5)!} = \frac{8!}{5!3!} = \frac{8 \times 7 \times 6}{3 \times 2 \times 1} = 56 ). Therefore, there are 56 possible combinations.
If you have 8 distinct numbers and want to create 8-digit combinations using each number exactly once, there are 8! (8 factorial) possible combinations. This is calculated as 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1, which equals 40,320. Therefore, you can make 40,320 unique 8-digit combinations with 8 distinct numbers.
it depends on which 8 numbers your talking about
7,893,600 (seven million, 8 hundred ninety-three thousand, 600) combinations in English.
There are 8*7/(2*1) = 28 combinations.
fifty * * * * * What sort of rubbish answer is that? There are 10C5 = 10*9*8*7*6/(5*4*3*2*1) = 252 combinations.