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10!/3! = 604800 different combinations.
Allowing repeats, but not leading 0s, the answer is 9,000,000,000
10C6 = 10*9*8*7/(4*3*2*1) = 210 combinations.
7
Assuming the digits cannot be repeated, there are 7 combinations with 1 digit, 21 combinations with 2 digits, 35 combinations with 3 digits, 35 combinations with 4 digits, 21 combinations with 5 digits, 7 combinations with 6 digits and 1 combinations with 7 digits. That makes a total of 2^7 - 1 = 127: too many for me to list. If digits can be repeated, there are infinitely many combinations.