With two bits, there are (2^2) possible combinations, which equals 4. The combinations are: 00, 01, 10, and 11. Each bit can be either 0 or 1, leading to these four distinct configurations.
6 Is how many different combinations there are
To represent 64 characters, you would need 6 bits. This is because 2^6 equals 64, meaning six bits can encode 64 different values, sufficient for each character. Each bit can represent two states (0 or 1), and with six bits, you can create combinations to represent all 64 characters.
There are twelve possible solutions using the rule you stated.
There are 72 permutations of two dice and one coin.
2 candidates * 5 vice-president candidates = 10 combinations.
45
For every bit, there are two combinations. For 12 bits, you need to multiply all together: 2 x 2 x 2 x ... x 2, or 2 to the power 12, which is equal to 4096.
6X6=36
Each of the 5 digits has two possibilities. So the total number of possible combinations is2 x 2 x 2 x 2 x 2 = 32 .(Another way to ask the same question is: How many binary numbers can you write with 5 bits ?)
In ASCII code, each letter, number or punctuation mark takes one byte, or 8 bits. That gives you 256 discrete combinations. Two letters take 2 bytes, or 16 bits.
10
3
A nibble (also known as a nybble or nyble) can represent half a character(two nibbles are needed for a valid ASCII character). A nibble is made up of 4 bits and those 4 bits are usually represented by a single hexadecimal value. 4 bits only allows for 16 combinations, 8 bits allows for 255. An ASCII character is represented by two hexadecimal characters, which is the same as 8 bits or two nibbles.
two thousand bits No, there are 8 bits in a byte.
6 Is how many different combinations there are
two bits are in a quarter of a dollar
4 * 2 = 8. 8 possible varieties.