6 Is how many different combinations there are
There are 72 permutations of two dice and one coin.
There are twelve possible solutions using the rule you stated.
2 candidates * 5 vice-president candidates = 10 combinations.
You have 6 choices of cards, two possibilities with the coin and 6 numbers on the cube. The number of combinations is : 6 x 2 x 6 = 72.
45
For every bit, there are two combinations. For 12 bits, you need to multiply all together: 2 x 2 x 2 x ... x 2, or 2 to the power 12, which is equal to 4096.
6X6=36
Each of the 5 digits has two possibilities. So the total number of possible combinations is2 x 2 x 2 x 2 x 2 = 32 .(Another way to ask the same question is: How many binary numbers can you write with 5 bits ?)
10
In ASCII code, each letter, number or punctuation mark takes one byte, or 8 bits. That gives you 256 discrete combinations. Two letters take 2 bytes, or 16 bits.
3
A nibble (also known as a nybble or nyble) can represent half a character(two nibbles are needed for a valid ASCII character). A nibble is made up of 4 bits and those 4 bits are usually represented by a single hexadecimal value. 4 bits only allows for 16 combinations, 8 bits allows for 255. An ASCII character is represented by two hexadecimal characters, which is the same as 8 bits or two nibbles.
Well, darling, if you're looking for the dynamic duo that multiplies to 145, look no further than 5 and 29. They may not be Batman and Robin, but they sure know how to get the job done. So, there you have it, 5 times 29 equals 145. Case closed.
two thousand bits No, there are 8 bits in a byte.
6 Is how many different combinations there are
4 * 2 = 8. 8 possible varieties.