With two bits, there are (2^2) possible combinations, which equals 4. The combinations are: 00, 01, 10, and 11. Each bit can be either 0 or 1, leading to these four distinct configurations.
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6 Is how many different combinations there are
There are twelve possible solutions using the rule you stated.
There are 72 permutations of two dice and one coin.
2 candidates * 5 vice-president candidates = 10 combinations.
You have 6 choices of cards, two possibilities with the coin and 6 numbers on the cube. The number of combinations is : 6 x 2 x 6 = 72.