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For every bit, there are two combinations.
For 12 bits, you need to multiply all together:
2 x 2 x 2 x ... x 2, or 2 to the power 12, which is equal to 4096.
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I have to pick 6 numbers out of 12 how many different combinations?
30
How many numbers consisting of two digits can be formed from 2 3 5 7 IF Each integer is to be used only once?
The sum you require is 4!/2!2!, which is 6. This means there are 6 different two-digit numbers. * * * * * Wrong! The above formula is for the number of combinations, not permutations. However, since the number 23 is different from the number 32, you require permutations and not combinations. There are 4*3 = 12 23, 25, 27, 32, 35, 37, 52, 53, 57, 72, 73, 75.
How many 6 number combinations between 1 and 15?
The answer is 15C6 = 15*14*13*12*11*10/(6*5*4*3*2*1) = 5,005
How many number combinations possible from a 13 digit number?
There is only one possible combination of a 13 digit number created from 13 digits. In a combination, the order of the digits does not matter so that 123 is the same as 132 or 312 etc. If there are 13 different digits (characters) there is 1 combination of 13 digits 13 combinations of 1 or of 12 digits 78 combinations of 2 or of 11 digits and so on There are 213 - 1 = 8191 in all. If the characters are not all different it is necessary to have more information.
What is the probability of rolling a sum of 7 with 2 dice?
Te probability of rolling a sum of 7 with two fair dice is 6 in 36, or 1 in 6, or about 0.1667.Of all the possible combinations of two dice, the sum of 7 has the highest probability, with the other combinations decreasing down to 2 and 12, with probabilities of 1 in 36, or about 0.0278.
