There are:
8C6 = 8!/6!(8-6)!
= (8 x 7)/(2 x 1)
= 28.
7 of them. Remember, that in a combination the order of the numbers does not matter.
They are called combinations!
120 WRONG! That is the number of PERMUTATIONS. In the case of combinations, the order of the numbers does not matter, so there is only 1 5-number combination from 5 numbers.
If order doesn't matter, 15 combinations and if order does matter, 360 combinations are possible.
There is only one combination since the order of the numbers in a combination does not matter.
7 of them. Remember, that in a combination the order of the numbers does not matter.
4 of them. In a combination the order of the numbers does not matter.
Just 4: 123, 124, 134 and 234. The order of the numbers does not matter with combinations. If it does, then they are permutations, not combinations.
10 Combinations (if order doesn't matter). 3,628,800 Possiblilities (if order matters).
You can get only four combinations: They are: 11, 118, 119 and 1189. In a combination, the order of the digits does not matter.
They are called combinations!
120 WRONG! That is the number of PERMUTATIONS. In the case of combinations, the order of the numbers does not matter, so there is only 1 5-number combination from 5 numbers.
If order doesn't matter, 15 combinations and if order does matter, 360 combinations are possible.
There is only one combination since the order of the numbers in a combination does not matter.
The answer depends on whether order matters. For example, would 1234 be considered the same as 4321. If order does not matter, there are only 15 combinations. This answer was obtained dividing the factorial 6 by the product of the factorial of 4 and the factorial of (6-4). In general, the amount of unordered combinations of x with y numbers is equal to y!/(x!(y-x)!). If order does matter, there are 360 combinations. This answer was obtained by diving the factorial of 6 by the factorial of (6-4). In general, the amount of ordered combinations of x with y numbers is equal to y!/((y-x)!).
If the order of the 4 numbers matters, then there are (6 x 5 x 4 x 3) = 360 .If the order of the 4 numbers doesn't matter, then there are 15 different groups of 4.
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