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There is only 1 combination of the numbers 123. (order does not matter)

There are 6 permutations of the numbers 123. (order does matter)

1 2 3

1 3 2

2 1 3

2 3 1

3 1 2

3 2 1

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Q: How many combinations of 123?
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Related questions

How many decimal combinations for 123?

Just one. In combinatorials, 123 is the same as 312 and so on.


How many combinations of three digits can be made from the numbers 123?

6


How many combinations of 3 numbers are there?

6 for example, 123 123 132 321 213 231 312 * * * * * WRONG. Those are permutations, not combinations. There are 8 possible combinations: 123 12 13 23 1 2 3 and finally, the null combination.


How many 3 number combinations are possible with 1234?

Just 4: 123, 124, 134 and 234. The order of the numbers does not matter with combinations. If it does, then they are permutations, not combinations.


How many combinations of three digits can be made from numbers 1 - 3?

Six combinations: 123, 132, 213, 231, 312, 321


How may combinations are in 123?

123 132 231 213 312 321


How many combinations can you make with 1 2 3?

well, 123 213 312 321 132 231 that's all


How many 6 number combinations using numbers 1 2 and 3 and what are they?

123 132 213 231 312 321


What are the combinations for a 3 digit number 1-4?

Assuming the digits are not repeated, there are four combinations:123, 124, 134 and 234.


How many 3 digit number can be using 123?

You can make six different combinations: 123 132 213 231 321 312. If you just need to know the number of combinations, you could find the answer without writing everything out by letting x represent the number of digits and calculating x*(x-1).


How many combinations the numbers one two and three using each digit only once can I get?

6 - 123, 132, 213, 231, 312, and 321.


How many combinations can you make with three numbers?

To calculate the number of combinations with three numbers, you would use the formula for combinations, which is nCr = n! / r!(n-r)!. In this case, n is the total number of numbers you have to choose from, and r is the number of numbers you are choosing. So, if you have three numbers to choose from, there would be 3C3 = 3! / 3!(3-3)! = 6 / (6*0!) = 6 / 6 = 1 combination.