six
Yes if drawn within an octagon from a vertex to each of the other vertices will give you 8 triangles within the octagon
A regular octagon can intersect lines depending on the orientation and position of those lines relative to the octagon. If the lines are drawn through or near the vertices or edges of the octagon, they may intersect at multiple points. However, if the lines are drawn parallel to the sides or far outside the octagon, they may not intersect it at all. The specific intersection points would depend on the mathematical equations of the lines and the coordinates of the octagon's vertices.
An octagon has 16 diagonals.
8
A segment.
No.
If all of the diagonals are drawn from a vertex of an octagon, how many triangles are formed
16 diagonals* * * * *5. To all vertices except itself and one each on either side.
it really isn't hard 5
5 triangles are formed.
2
Yes if drawn within an octagon from a vertex to each of the other vertices will give you 8 triangles within the octagon
No, not if it is a randomly-drawn 8-vertex shape. Octagons only have all- obtuse angles if it is a regular octagon, like the shape of a stop sign.
In a regular pentagon, the lines of symmetry are drawn from each vertex to the midpoint of the edge directly opposite the vertex, so there are five in all.
A regular octagon has 8 lines of symmetry. See the Related Link below that includes a diagram of an octagon with the lines of symmetry drawn. A non-symmetrical octagon may have between 0-4 lines of symmetry.
An octagon has 16 diagonals.
No, I think 5 diagonals would be the maximum from a particular vertex. Let's label the vertices [A through H].For this example, they go clockwise, starting with A and going around to H, so looking at A: B & H are adjacent and both of the segments AB and AH are actually sides of the octagon, not diagonals. The remaining diagonals, from A are:ACADAEAFAG