Q: There are 6 diagonals that can be drawn from one vertex of an octagon?

Write your answer...

Submit

Still have questions?

Continue Learning about Other Math

16 diagonals* * * * *5. To all vertices except itself and one each on either side.

The number of Diagonals in one vertex of a Triangle is 0 (zero)..

There are 10 possible diagonals drawn from one vertex of the 13-gon which divide it into 11 nonoverlapping triangles.

If you mean "How many diagonals can be drawn from one vertex of a figure with 16 sides", the formula is n-3, where "n" being the number of sides of the figure. So 16-3 = 13 diagonals that can be drawn from one vertex.

12-3 = 9

Related questions

16 diagonals* * * * *5. To all vertices except itself and one each on either side.

The number of Diagonals in one vertex of a Triangle is 0 (zero)..

Number of sides minus two equals number of diagonals drawn from one vertex.

No, I think 5 diagonals would be the maximum from a particular vertex. Let's label the vertices [A through H].For this example, they go clockwise, starting with A and going around to H, so looking at A: B & H are adjacent and both of the segments AB and AH are actually sides of the octagon, not diagonals. The remaining diagonals, from A are:ACADAEAFAG

There are 10 possible diagonals drawn from one vertex of the 13-gon which divide it into 11 nonoverlapping triangles.

3

In a 54-sided polygon, 53 possible diagonals can be drawn from one vertex to another. These diagonals will not intersect. Therefore, the interior will be divided into 54 regions by the 53 diagonals plus the two sides of the original polygon that adjoin the vertex from which the diagonals are drawn.

36

You Can Get 6 triangles

If you mean "How many diagonals can be drawn from one vertex of a figure with 16 sides", the formula is n-3, where "n" being the number of sides of the figure. So 16-3 = 13 diagonals that can be drawn from one vertex.

12-3 = 9

8