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How many diagonals can be drawn from each vertex of an octagon?
Wiki User
∙ 12y ago
it really isn't hard 5
Wiki User
∙ 12y ago
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How do you find diagonals in a polygon?
Suppose a polygon has n vertices (and sides). From each vertex, a diagonal can be drawn to all vertices, excluding itself and the two adjacent vertices. So n-3 diagonals can be drawn from each vertex. Multiplying by the full complement of n vertices gives n(n-3). However, as things stand we have counted each diagonal twice: once at both ends. Dividing by two gives the actual number of diagonals. number of diagonals = n(n-3)/2
How many diagonals come from each vertex of a hexagon?
Three.
How many pairs of parallel diagonals in an octagon?
This assumes you mean a regular octagon. There are 4 pairs where the diagonals each skip two vertices. Then there are 4 sets of three parallel diagonals where one is the main diagonal (skips three vertices) and two skip just one vertex. For each of these sets of three, you can choose three pairs of two. That makes 12 pairs all up. So there are 4 + 12 = 16 pairs.
A hexagon can be divided into how many triangles by drawing all of the diagonals from one vertex?
A hexagon (six-sided polygon) can be divided into 4 triangles by drawing all of the diagonals from one vertex (only three lines can be drawn in this case, since each vertex already connects to two others on the edges of the form). If you instead drew lines from the center to each vertex, you would get 6 triangles.
What are the total number of diagonals in a hexagonal prism?
From each vertex, N-4 diagonals can be drawn, where N is the number of vertices. The total number of diagonals in a prism will be N(N-4)/2, where N is the number of vertices. For N=12 (a hexagonal prism) The total number of diagonals is 12*8/2=48 Answer:48
How many diagonals does each vertex have in an octagon?
5
How many diagonals can be drawn from one vertex of a regular octagon?
16 diagonals* * * * *5. To all vertices except itself and one each on either side.
How many diagonals can be drawn fron a vertex of an n-gon?
n-3 from each vertex.
How many diagonals can be drawn from one vertex of a polygon of 50 sides?
47 sides. Take a vertex of an n-sided polygon. There are n-1 other vertices. It is already joined to its 2 neighbours, leaving n-3 other vertices not connected to it. Thus n-3 diagonals can be drawn in from each vertex. For n=50, n-3 = 50-3 = 47 diagonals can be drawn from each vertex. The total number of diagonals in an n-sided polygon would imply n-3 diagonals from each of the n vertices giving n(n-3). However, the diagonal from vertex A to C would be counted twice, once for vertex A and again for vertex C, thus there are half this number of diagonals, namely: number of diagonals in an n-sided polygon = n(n-3)/2.
Can you draw eight triangles withh six lines?
Yes if drawn within an octagon from a vertex to each of the other vertices will give you 8 triangles within the octagon
What can you say about the relationship of the number of diagonals that can be drawn from each vertex of a polygon?
The formula for the number of diagonals is: 0.5*(n^2-3n) whereas 'n' is the number of sides of the polygon
How many straight diagonals does an octagon have?
An octagon has four (4) diagonals, each connecting two opposite vertices.
How many diagonals can be drawn from one vertex of a seven sided polygon?
There can be 14 lines in a seven side shape * * * * * That is the total number of diagonals from ALL vertices. Not what the question asked, though. From one vertex, there can be 4. One to every other vertex except for itself and one each on either side.
How do you find diagonals in a polygon?
Suppose a polygon has n vertices (and sides). From each vertex, a diagonal can be drawn to all vertices, excluding itself and the two adjacent vertices. So n-3 diagonals can be drawn from each vertex. Multiplying by the full complement of n vertices gives n(n-3). However, as things stand we have counted each diagonal twice: once at both ends. Dividing by two gives the actual number of diagonals. number of diagonals = n(n-3)/2
How many diagonals can be drawn from a vertex of an n-gon?
An n-gon has n(n-3)/2 total diagonals. You can draw n-3 diagonals from each vertex ( n>3) ( A triangle doesn't really have a diagonal) An alternative way of seeing this: from any vertex, you can draw a diagonal to any other vertex except itself and the immediate neighbour on either side (the latter would be sides of the n-gon). This gives n-3 diagonals.
What is a diagonal vertex of a square?
The diagonals of a square bisect each corner or vertex of the square.
How many diagonals come from each vertex of a hexagon?
Three.
