5 diagonals
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That is not correct since two of these would be lines joining the vertex to adjacent vertices (one on either side). These are sides of the polygon, not diagonals. The number of diagonals from any vertex of a polygon with n sides is n-3.
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four * * * * * The correct answer is 3. You cannot have a diagonal from a vertex to itself, nor to either of the two adjacent vertices (these would form sides of the polygon). So 3 out of the other vertices cannot be used. In a hexagon, that leaves 3 that can be used. Hence the answer.
Just one diagonal will divide a hexagon into two halves
110.Improved Answer:-It is 4
six
An n-gon has n(n-3)/2 total diagonals. You can draw n-3 diagonals from each vertex ( n>3) ( A triangle doesn't really have a diagonal) An alternative way of seeing this: from any vertex, you can draw a diagonal to any other vertex except itself and the immediate neighbour on either side (the latter would be sides of the n-gon). This gives n-3 diagonals.