four
* * * * *
The correct answer is 3.
You cannot have a diagonal from a vertex to itself, nor to either of the two adjacent vertices (these would form sides of the polygon). So 3 out of the other vertices cannot be used. In a hexagon, that leaves 3 that can be used. Hence the answer.
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110.Improved Answer:-It is 4
9 diagonals
You can draw 9 diagonals inside a hexagon.
5 diagonals * * * * * That is not correct since two of these would be lines joining the vertex to adjacent vertices (one on either side). These are sides of the polygon, not diagonals. The number of diagonals from any vertex of a polygon with n sides is n-3.
Depends on the shape.