Wiki User
∙ 12y agoWant this question answered?
Be notified when an answer is posted
2,598,960.
It is 0.0039 approx.
The answer depends on how many cards are dealt out to you - which depends on how many cards you are dealt.
These Cards We're Dealt was created in 2004.
The probability that the first four cards are face cards is (16/52)*(15/51)*(14/50)*(13/49) = 43680/6497400 = approx 0.0067
2,598,960.
It is 0.0039 approx.
23
Bridge uses a standard deck of 52 cards -- four suits (clubs, diamonds, hearts, spades) of 13 cards each. The four players are each dealt 13 cards.
There are 13 clubs in a standard deck of 52 cards. The probability, then, of drawing club is 13 in 52, or 1 in 4, or 0.25.
The answer depends on how many cards are dealt out to you - which depends on how many cards you are dealt.
These Cards We're Dealt was created in 2004.
The probability, if the cards are dealt often enough, is 1.On a single deal, the prob is 3.69379*10^-6
The minimum number of cards that must be dealt, from an arbitrarily shuffled deck of 52 cards, to guarantee that three cards are from some same suit is 9.The basis for 9 is that the first four cards could be from four different suits, the next four cards could be from four different suits, and the ninth card is guaranteed to match the suit of two of the previously dealt cards. The minimum number, without the guarantee, is 3, but the probability of that is only 0.052, or about 1 in 20.
The probability that the first four cards are face cards is (16/52)*(15/51)*(14/50)*(13/49) = 43680/6497400 = approx 0.0067
The answer depends on how many cards you are dealt!
It is 1 in 17. Here's why: There are 52 cards in a deck, 13 different value cards (A, 2, 3, etc.), and two cards are dealt. We're finding the odds of getting any pocket pair, not just one. This means that the first card dealt can be any value. The second card has to repeat the value of the first card. For example, the first card dealt is a 10, and now the second card has to be a 10. After the first 10 is dealt, there are 51 cards left in the deck, and 3 different 10's. Therefore, 3 over 51 simplifies to 1 over 17.