Wiki User
∙ 11y ago506 = 15,625 million
Wiki User
∙ 11y agoIf the numbers can be repeated and the numbers are 0-9 then there are 1000 different combinations.
If numbers may be repeated . . . 36 If numbers may not be repeated . . . 30 If the sequence doesn't matter . . . 15
120
10 x 9 x 8 = 720 different arrangements If the sequence doesn't matter, then there are (720/6) = 120 different bunches
If you exclude numbers starting with zero then the first digit must be between 1 and 9 (i.e. 9 combinations). The remaining 9 digits can be any value between 0 and 9 (i.e. 10 combinations).So you can have 9x109 = 9,000,000,000 combinations.
If you can repeat the numbers within the combination there are 10,000 different combinations. If you cannot repeat the numbers within the combination, there are 5040 different combinations.
10
If the sequence matters: 720If the sequence doesn't matter: 120
13579
There are 7 combinations. Each combination excludes a different one of the seven numbers.
there are 13,983,816 combinations.
56 combinations. :)
If the sequence is important, then there are (12 x 11 x 10 x 9 x 8) = 95,040 different ones. If only the members of the group are important but not their the sequence, then there are 95,040 / (5 x 4 x 3 x 2 x 1) = 792 combinations, each with different members. The formulas are: Permutations = 12! / 7! Combinations = 12! / (7! x 5!)
If the numbers can be repeated and the numbers are 0-9 then there are 1000 different combinations.
If numbers may be repeated . . . 36 If numbers may not be repeated . . . 30 If the sequence doesn't matter . . . 15
120
10 x 9 x 8 = 720 different arrangements If the sequence doesn't matter, then there are (720/6) = 120 different bunches