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Q: How many combinations of 5 different numbers if there are 5 numbers?
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Related questions

How many different combinations of 5 numbers 5 number combination?

120 WRONG! That is the number of PERMUTATIONS. In the case of combinations, the order of the numbers does not matter, so there is only 1 5-number combination from 5 numbers.


How many combinations are there with 5 numbers?

5*4*3*2*1 = 120 combinations. * * * * * No. The previous answerer has confused permutations and combinations. There are only 25 = 32 combinations including the null combinations. There is 1 combination of all 5 numbers There are 5 combinations of 4 numbers out of 5 There are 10 combinations of 3 numbers out of 5 There are 10 combinations of 2 numbers out of 5 There are 5 combinations of 1 numbers out of 5 There is 1 combination of no 5 numbers 32 in all, or 31 if you want to disallow the null combination.


How many combinations can you make with the numbers 2 3 6 7 and 8?

You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.


How many combinations of 5 are there in 0 to 10 numbers?

There are a huge number of combinations of 5 numbers when using the numbers 0 through 10. There are 10 to the 5th power combinations of these numbers.


How many number combinations are there if there are six numbers and you have to have a four number combination?

all numbers have to be different 720 360 (6*5*4*3*2*1), * * * * * Wrong. Combinations do not have to be different. Those are permutations. There are only 6C4 = 6*5/(2*1) = 15 combinations.


How many different 4 digit combinations are there for numbers 1 2 3 4 5 and last numbers are 4 5 no restrictions numbers can be repeated?

9


How many different 5 number combinations can you get using numbers 1 through 39 with no doubles?

575757


How many combinations of 5 numbers are there in 31 numbers?

31C5 = 169911


How many different combinations of 5 numbers can you get from the numbers 1 -25 with no number repeated in a combination?

To calculate the number of different combinations of 5 numbers chosen from 1 to 25 without repetition, we can use the formula for combinations: nCr = n! / r!(n-r)!. In this case, n = 25 (total numbers) and r = 5 (numbers chosen). Therefore, the number of combinations is 25! / (5!(25-5)!) = 53,130 different combinations.


How many combinations in sets of 5 using the numbers 1 thru 10?

There are 252 combinations.


How many combinations can you get out of 40 numbers in groups of 6?

5


How many different 3 item combinations can you get out of 5 different items?

whenever you have a question like this, just multiply the two numbers together and you got your answer.