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If the sequence is important, then there are (12 x 11 x 10 x 9 x 8) = 95,040 different ones.
If only the members of the group are important but not their the sequence, then
there are
95,040 / (5 x 4 x 3 x 2 x 1) = 792 combinations, each with different members.
The formulas are:
Permutations = 12! / 7!
Combinations = 12! / (7! x 5!)
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How many 4 number combination are in 6 numbers?
There are 15 combinations.
How many combinations can you make with three numbers?
To calculate the number of combinations with three numbers, you would use the formula for combinations, which is nCr = n! / r!(n-r)!. In this case, n is the total number of numbers you have to choose from, and r is the number of numbers you are choosing. So, if you have three numbers to choose from, there would be 3C3 = 3! / 3!(3-3)! = 6 / (6*0!) = 6 / 6 = 1 combination.
If using 7 single digit numbers how many different combinations can you get?
Number of 7 digit combinations out of the 10 one-digit numbers = 120.
How many number combinations are there in 0-9999?
9999
How many combinations can you make with the numbers 2 3 6 7 and 8?
You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.
