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If the sequence is important, then there are (12 x 11 x 10 x 9 x 8) = 95,040 different ones.

If only the members of the group are important but not their the sequence, then

there are

95,040 / (5 x 4 x 3 x 2 x 1) = 792 combinations, each with different members.

The formulas are:

Permutations = 12! / 7!

Combinations = 12! / (7! x 5!)

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14y ago

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