This is a question involving permutations and possibilities.Nine numbers, four slots to fill, and I'll assume no duplicates for now.
9!/(4!(9-4)!)
= 6*7*8*9 / 24
= 7*8*9 / 4
= 7*2*9
= 63*2
= 126
There are 126 unique four-digit numbers that can be arranged with the digits 1-9.
If duplicates were allowed, there would be 94possibilities, or 6,561.
how make the answer im don/now
9876 is the largest four digit number you can make if all the digits must be different.
8
Ten different digits can be used to make 10C4 = 10*9*8*7/(4*3*2*1) = 210 four-digit numbers. Either numbers starting with 0 are permitted or the 10 digits do not contain a 0.
The four-digit numbers that can be formed using the digits 6, 7, 8, and 9, without repetition, are all the permutations of these four digits. There are 24 possible combinations, including numbers like 6789, 6798, 6879, and so on. Essentially, any arrangement of these four digits constitutes a valid four-digit number.
how make the answer im don/now
9876 is the largest four digit number you can make if all the digits must be different.
9
8
Ten different digits can be used to make 10C4 = 10*9*8*7/(4*3*2*1) = 210 four-digit numbers. Either numbers starting with 0 are permitted or the 10 digits do not contain a 0.
The four-digit numbers that can be formed using the digits 6, 7, 8, and 9, without repetition, are all the permutations of these four digits. There are 24 possible combinations, including numbers like 6789, 6798, 6879, and so on. Essentially, any arrangement of these four digits constitutes a valid four-digit number.
6, as long as they are all different
9
First digit can be any of 3, second can be any of 3, as can third and fourth so your answer is 3 to the fourth ie 81
4! = 24 ■
3024
If you want 4-digit numbers, there are 24 of them.