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Since 0-9 has 10 different digits in it, you can calculate the amount of four digit numbers (non-repeating) by multiplying 10*9*8*7. That equals 5040.

Q: How many four digit numbers can you make using 0-9 only using each number once?

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998,000

There are 5 numbers which can make the 3 digit numbers in this example. Therefore each digit in the 3 digit number has 5 choices of which number can be placed there. Therefore number of 3 digit numbers = 5 x 5 x 5 = 125

-123456786

4 options for the first digit, 3 options for the second digit, 2 options for the third digit. Multiply the number of options together, and you find how many 3-digit numbers you can get.

This is not possible, since there are only five single digit odd numbers, which are 1, 3, 5, 7 and 9.

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998,000

There are 5 numbers which can make the 3 digit numbers in this example. Therefore each digit in the 3 digit number has 5 choices of which number can be placed there. Therefore number of 3 digit numbers = 5 x 5 x 5 = 125

There are four of each.

-123456786

4 options for the first digit, 3 options for the second digit, 2 options for the third digit. Multiply the number of options together, and you find how many 3-digit numbers you can get.

24 = 4*3*2*1 of them

61

This is not possible, since there are only five single digit odd numbers, which are 1, 3, 5, 7 and 9.

the place of each digit help the value of the number by using your multuplication

For each number, there are four digits, and for each digit, there are two possibilities for digits: 3 or 4. So the number of 4-digit numbers is 2*2*2*2 = 16. The 4-digit numbers using 3 and 4 are: 3333 3334 3343 3344 3433 3434 3443 3444 4333 4334 4343 4344 4433 4434 4443 4444

6*5*4*3=360

Assuming that the first digit of the 4 digit number cannot be 0, then there are 9 possible digits for the first of the four. Also assuming that each digit does not need to be unique, then the next three digits of the four can have 10 possible for each. That results in 9x10x10x10 = 9000 possible 4 digit numbers. If, however, you can not use the same number twice in completing the 4 digit number, and the first digit cannot be 0, then the result is 9x9x8x7 = 4536 possible 4 digit numbers. If the 4 digit number can start with 0, then there are 10,000 possible 4 digit numbers. If the 4 digit number can start with 0, and you cannot use any number twice, then the result is 10x9x8x7 = 5040 possilbe 4 digit numbers.