By ordering the digits, you can make 4*3*2*1 = 24 different numbers.
By using mathematical operations that are already defined (addition, power, trigonometric functions etc), you can make many more - at least millions. If you then include functions that you define, the answer is infinitely many.
about... 25 just take 5 numbers times 5 numbers
6 2-digit numbers (13/15/35/53/51/31)
55----------------------------------------------------------------------------------------------From Rafaelrz.You can make, 5! = 120, five digit numbers using 1,2,3,4 and 6.
106------------------------------------------------------------------------------------------------From Rafaelrz.You can make, 4P3 = 4!/(4-3)! = 24, different 3 digit numbers using 1, 2, 3 and 4.
256!
Assuming that the six numbers are different, the answer is 15.
48
Their is 25 combinations
120
If you want 4-digit numbers, there are 24 of them.
Infinite
2 and 17
7 + 2 + 2 5 + 3 + 3 5 + 2 + 2 + 2 2 + 3 + 3 + 3 2 + 2 + 2 + 2 + 3
If the six numbers are all different, then the answer is 6C4 = 6*5/(2*1) = 15
2
Assuming the 36 numbers are all different, there are 36*35/2 = 630 pairs.
2