15
6, as long as they are all different
6 if all digits are different, 27 otherwise.
106------------------------------------------------------------------------------------------------From Rafaelrz.You can make, 4P3 = 4!/(4-3)! = 24, different 3 digit numbers using 1, 2, 3 and 4.
about... 25 just take 5 numbers times 5 numbers
55----------------------------------------------------------------------------------------------From Rafaelrz.You can make, 5! = 120, five digit numbers using 1,2,3,4 and 6.
6, as long as they are all different
If the only operation is addition, then 3.
6 if all digits are different, 27 otherwise.
106------------------------------------------------------------------------------------------------From Rafaelrz.You can make, 4P3 = 4!/(4-3)! = 24, different 3 digit numbers using 1, 2, 3 and 4.
about... 25 just take 5 numbers times 5 numbers
48
There are two different numbers. 3 and 7
120
If you want 4-digit numbers, there are 24 of them.
55----------------------------------------------------------------------------------------------From Rafaelrz.You can make, 5! = 120, five digit numbers using 1,2,3,4 and 6.
There are 6!/3! = 120 different 3-digit numbers that can be made from these 6 digits.
By ordering the digits, you can make 4*3*2*1 = 24 different numbers. By using mathematical operations that are already defined (addition, power, trigonometric functions etc), you can make many more - at least millions. If you then include functions that you define, the answer is infinitely many.