18
To determine how many different 9-member teams can be chosen from 12 students, we can use the combination formula ( C(n, k) = \frac{n!}{k!(n-k)!} ). Here, ( n = 12 ) and ( k = 9 ). This can also be expressed as ( C(12, 9) = C(12, 3) ), which simplifies the calculation. Thus, ( C(12, 3) = \frac{12!}{3! \cdot 9!} = \frac{12 \times 11 \times 10}{3 \times 2 \times 1} = 220 ). Therefore, there are 220 different 9-member teams that can be formed.
To determine how many different teams of 9 can be chosen from 12 students, we use the combination formula (C(n, k) = \frac{n!}{k!(n-k)!}), where (n) is the total number of students and (k) is the number of students to choose. Here, (n = 12) and (k = 9). Thus, the calculation is (C(12, 9) = C(12, 3) = \frac{12!}{3! \cdot 9!} = \frac{12 \times 11 \times 10}{3 \times 2 \times 1} = 220). Therefore, there are 220 different teams of 9 that can be chosen from 12 students.
two
252 teams.
75
18
2 groups. 2 x 3= 6
20 is the answer because 6!/(6-3)!3!=6 times 5 times 4/3 times 2 times 1=20
To determine how many different 9-member teams can be chosen from 12 students, we can use the combination formula ( C(n, k) = \frac{n!}{k!(n-k)!} ). Here, ( n = 12 ) and ( k = 9 ). This can also be expressed as ( C(12, 9) = C(12, 3) ), which simplifies the calculation. Thus, ( C(12, 3) = \frac{12!}{3! \cdot 9!} = \frac{12 \times 11 \times 10}{3 \times 2 \times 1} = 220 ). Therefore, there are 220 different 9-member teams that can be formed.
No.
1 team of 36 students 2 teams of 18 3 teams of 12 4 teams of 9 6 teams of 6 9 teams of 4 12 teams of 3 18 teams of 2 and 36 teams of 1
Can you provide more context or details on the teams you are referring to?
Any 5 from 7 is (7 x 6)/2 ie 21.
To support emergency management operations.
C105 = 10 ! / (5!x(10-5)!) = 10! /5!2 = 252
Divide then into 5 teams of 5 students