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To determine how many different two-member teams can be formed from six students, you can use the combination formula ( C(n, r) = \frac{n!}{r!(n-r)!} ), where ( n ) is the total number of students and ( r ) is the number of team members. In this case, ( n = 6 ) and ( r = 2 ). Thus, the calculation is ( C(6, 2) = \frac{6!}{2!(6-2)!} = \frac{6 \times 5}{2 \times 1} = 15 ). Therefore, 15 different two-member teams can be formed from six students.
What else can I help you with?
How many different 3 member teams can be formed from a group of 6 students?
18
How many different 9-member teams can be chosen from 12 students?
To determine how many different 9-member teams can be chosen from 12 students, we can use the combination formula ( C(n, k) = \frac{n!}{k!(n-k)!} ). Here, ( n = 12 ) and ( k = 9 ). This can also be expressed as ( C(12, 9) = C(12, 3) ), which simplifies the calculation. Thus, ( C(12, 3) = \frac{12!}{3! \cdot 9!} = \frac{12 \times 11 \times 10}{3 \times 2 \times 1} = 220 ). Therefore, there are 220 different 9-member teams that can be formed.
How many different teams of 3 can be formed from a class of 24 students?
To find the number of different teams of 3 that can be formed from a class of 24 students, we can use the combination formula ( C(n, r) = \frac{n!}{r!(n-r)!} ). Here, ( n = 24 ) and ( r = 3 ). Thus, the calculation is ( C(24, 3) = \frac{24!}{3!(24-3)!} = \frac{24 \times 23 \times 22}{3 \times 2 \times 1} = 2024 ). Therefore, 2024 different teams of 3 can be formed.
How many different teams of 9 can be chosen from 12 students?
To determine how many different teams of 9 can be chosen from 12 students, we use the combination formula (C(n, k) = \frac{n!}{k!(n-k)!}), where (n) is the total number of students and (k) is the number of students to choose. Here, (n = 12) and (k = 9). Thus, the calculation is (C(12, 9) = C(12, 3) = \frac{12!}{3! \cdot 9!} = \frac{12 \times 11 \times 10}{3 \times 2 \times 1} = 220). Therefore, there are 220 different teams of 9 that can be chosen from 12 students.
How many three person relay teams can be chosen from six students?
two
How many different three-member teams can be formed from six students?
75
How many different 3 member teams can be formed from a group of 6 students?
18
How many three member teams can be formed from a group of six students?
2 groups. 2 x 3= 6
How many different three member teams can be formed from six students?
20 is the answer because 6!/(6-3)!3!=6 times 5 times 4/3 times 2 times 1=20
How many different 9-member teams can be chosen from 12 students?
To determine how many different 9-member teams can be chosen from 12 students, we can use the combination formula ( C(n, k) = \frac{n!}{k!(n-k)!} ). Here, ( n = 12 ) and ( k = 9 ). This can also be expressed as ( C(12, 9) = C(12, 3) ), which simplifies the calculation. Thus, ( C(12, 3) = \frac{12!}{3! \cdot 9!} = \frac{12 \times 11 \times 10}{3 \times 2 \times 1} = 220 ). Therefore, there are 220 different 9-member teams that can be formed.
How many different teams of 3 can be formed from a class of 24 students?
To find the number of different teams of 3 that can be formed from a class of 24 students, we can use the combination formula ( C(n, r) = \frac{n!}{r!(n-r)!} ). Here, ( n = 24 ) and ( r = 3 ). Thus, the calculation is ( C(24, 3) = \frac{24!}{3!(24-3)!} = \frac{24 \times 23 \times 22}{3 \times 2 \times 1} = 2024 ). Therefore, 2024 different teams of 3 can be formed.
Can 100 students arrange themselves in 7 different teams if there are to be the same number of students on each side?
No.
When 36 students are to be divided in to teams of equal size how many different ways can the students be divided?
1 team of 36 students 2 teams of 18 3 teams of 12 4 teams of 9 6 teams of 6 9 teams of 4 12 teams of 3 18 teams of 2 and 36 teams of 1
How many different teams of 9 can be chosen from 12 students?
To determine how many different teams of 9 can be chosen from 12 students, we use the combination formula (C(n, k) = \frac{n!}{k!(n-k)!}), where (n) is the total number of students and (k) is the number of students to choose. Here, (n = 12) and (k = 9). Thus, the calculation is (C(12, 9) = C(12, 3) = \frac{12!}{3! \cdot 9!} = \frac{12 \times 11 \times 10}{3 \times 2 \times 1} = 220). Therefore, there are 220 different teams of 9 that can be chosen from 12 students.
How many different five-person relay teams can be chosen from 7 students?
Any 5 from 7 is (7 x 6)/2 ie 21.
These teams are formed in support of your installations's DRF?
Can you provide more context or details on the teams you are referring to?
Why teams are formed?
To support emergency management operations.
