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To determine how many different teams of 9 can be chosen from 12 students, we use the combination formula (C(n, k) = \frac{n!}{k!(n-k)!}), where (n) is the total number of students and (k) is the number of students to choose. Here, (n = 12) and (k = 9). Thus, the calculation is (C(12, 9) = C(12, 3) = \frac{12!}{3! \cdot 9!} = \frac{12 \times 11 \times 10}{3 \times 2 \times 1} = 220). Therefore, there are 220 different teams of 9 that can be chosen from 12 students.
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How many three person relay teams can be chosen from six students?
two
How many different basketball teams of 5 people can be chosen from 10 people?
252 teams.
How many different groups of 5 students can be chosen from 23 students?
if order does not matter then, (23x22x21x20x19)/(5x4x3x2x1) = 33,649
How many different 3 member teams can be formed from a group of 6 students?
18
How many different 9-member teams can be chosen from 12 students?
To determine how many different 9-member teams can be chosen from 12 students, we can use the combination formula ( C(n, k) = \frac{n!}{k!(n-k)!} ). Here, ( n = 12 ) and ( k = 9 ). This can also be expressed as ( C(12, 9) = C(12, 3) ), which simplifies the calculation. Thus, ( C(12, 3) = \frac{12!}{3! \cdot 9!} = \frac{12 \times 11 \times 10}{3 \times 2 \times 1} = 220 ). Therefore, there are 220 different 9-member teams that can be formed.
How many three person relay teams can be chosen from six students?
two
How many different five-person relay teams can be chosen from 7 students?
Any 5 from 7 is (7 x 6)/2 ie 21.
How many different basketball teams of 5 people can be chosen from 10 people?
252 teams.
How many different five-person relay teams can be chosen from 10 students?
C105 = 10 ! / (5!x(10-5)!) = 10! /5!2 = 252
How many different three-member teams can be formed from six students?
75
Is this a permutation In how many different ways could a committee of 5 students be chosen from a class of 25 students?
6,375,600
How many different groups of 5 students can be chosen from 23 students?
if order does not matter then, (23x22x21x20x19)/(5x4x3x2x1) = 33,649
How many different 3 member teams can be formed from a group of 6 students?
18
How many different 9-member teams can be chosen from 12 students?
To determine how many different 9-member teams can be chosen from 12 students, we can use the combination formula ( C(n, k) = \frac{n!}{k!(n-k)!} ). Here, ( n = 12 ) and ( k = 9 ). This can also be expressed as ( C(12, 9) = C(12, 3) ), which simplifies the calculation. Thus, ( C(12, 3) = \frac{12!}{3! \cdot 9!} = \frac{12 \times 11 \times 10}{3 \times 2 \times 1} = 220 ). Therefore, there are 220 different 9-member teams that can be formed.
How many ways can an adviser chosen 4 students from a class of 12 if they are given a different task?
There are 11880 ways.
4 students in a class of 12. How many ways can the students be chosen if they are each given a different task?
To determine how many ways 4 students can be chosen from a class of 12 and assigned different tasks, we first select 4 students from the 12, which can be done in ( \binom{12}{4} ) ways. Then, we can assign the 4 different tasks to these students in ( 4! ) (24) ways. Therefore, the total number of ways to choose the students and assign the tasks is ( \binom{12}{4} \times 4! = 495 \times 24 = 11,880 ).
How many ways can a committeee of 6 be chosen from 5 teachers and 4 students if the committee must includes three teachers and three students?
There are 10 different sets of teachers which can be combined with 4 different sets of students, so 40 possible committees.
