Two: '0' or '1'
A 4-bit binary number can represent (2^4 = 16) different values. This range includes all combinations of 0s and 1s that can be formed with four bits, ranging from 0000 (0 in decimal) to 1111 (15 in decimal). Thus, the values it can represent are 0 through 15.
An 8-bit binary number consists of 8 symbols, each of which can be either a 0 or a 1. This means that there are two possible values for each bit. Therefore, an 8-bit binary number can represent a total of (2^8 = 256) different values.
The range of an 8-bit unsigned integer is from 0 to 255. This is because an 8-bit unsigned integer can represent 2^8 (or 256) different values, starting from 0 and going up to 255. Each bit can be either 0 or 1, allowing for all combinations within that range.
A binary system can represent two distinct states, typically denoted as 0 and 1. Each bit in a binary system can hold one of these two values. When multiple bits are combined, the number of distinct states increases exponentially; for example, an n-bit binary system can represent 2^n distinct states.
Well, honey, in an 8-bit register, you can store a total of 256 different binary values. That's because each bit can be either a 0 or a 1, giving you 2 options per bit. And when you have 8 bits, you just multiply 2 by itself 8 times to get 256. Math doesn't lie, darling.
A 128-bit register can store 2 128th (over 3.40 × 10 38th) different values. The range of integer values that can be stored in 128 bits depends on the integer representation used.
An 8-bit binary number consists of 8 symbols, each of which can be either a 0 or a 1. This means that there are two possible values for each bit. Therefore, an 8-bit binary number can represent a total of (2^8 = 256) different values.
A 4-bit sound allows for 2^4 = 16 levels of amplitude. This means that the sound can represent 16 different discrete values of amplitude.
1. A single bit can represent two different values, 0 and 1. Then simply take the largest of those two possible values, 1, and that's your answer.
0 o 1
210 = 1024, so there are 1024 different bit configurations in a 10-bit code.
4, which is equal to 2 to the power 2.In general, with "n" bits, you can have "2 to the power n" different states (or represent that many different numbers).
4.1 bit for 2,2 bits for 4,3 bits for 8,4 bits for 16.
Neither of the following are true about 1 bit, it can not represent decimal values 0 and 9 nor can it be used to represent one character in the lowercase English alphabet and one binary digit four binary. A true statement would be that 1 bit is represented by the decimal values 0 or 1.
24, or 16 (0 through 15) One binary digit (bit) can have 21 values (0 or 1). Two bits can have 22 values. Three bits can have 23 values. A five-bit number can have 25 values... and so on...
With 4 bits, you can represent 2^4 or 16 different numbers. This is because each bit can have 2 possible values (0 or 1), so with 4 bits you have 2 x 2 x 2 x 2 = 16 possible combinations. These numbers range from 0 to 15 in decimal representation.
We need signed integers in order to represent both negative and positive values. However, some numbers can never be negative. For instance, the size of a file must always be greater than or equal to zero so we use unsigned integers to represent file sizes. Also, natural numbers must be greater than 0 so there's no point in using a signed value to represent a natural number. Signed integers also use one bit to denote the sign, but unsigned integers do not thus unsigned integers can effectively represent twice the range of positive values than an unsigned integer can. For instance, an 8-bit signed value can represent values in the range -128 to +127 using twos complement notation, but an 8-bit signed value can represent values in the range 0 to 255.