A 128-bit register can store 2 128th (over 3.40 × 10 38th) different values. The range of integer values that can be stored in 128 bits depends on the integer representation used.
24, or 16 (0 through 15) One binary digit (bit) can have 21 values (0 or 1). Two bits can have 22 values. Three bits can have 23 values. A five-bit number can have 25 values... and so on...
1. A single bit can represent two different values, 0 and 1. Then simply take the largest of those two possible values, 1, and that's your answer.
Since there are 8 bits in between, and they can assume any of the two values (0 or 1), that results in a total of 28 different combinations.
0 and 1
A 128-bit register can store 2 128th (over 3.40 × 10 38th) different values. The range of integer values that can be stored in 128 bits depends on the integer representation used.
Two: '0' or '1'
For signed 32 bit values: 2^31-1 = 0x7FFFFFFF = 2,147,483,647 For unsigned 32 bit values: 2^32-5 = 0xFFFFFFFB = 4,294,967,291
24, or 16 (0 through 15) One binary digit (bit) can have 21 values (0 or 1). Two bits can have 22 values. Three bits can have 23 values. A five-bit number can have 25 values... and so on...
Texas is too big, but you can fit in a Ohio, Maryland, and part of West Virginia. But seriously though...I am assuming that you mean "how many unique combinations of 1's and 0's can be stored in a 16 bit register." The answer is given as 2 (the number of different possibilities per digit) raised to the power of 16. The answer is 65536, made up of 0 through 65535. An 8 bit register can represent 256 different values, 0 through 255.
A 4-bit sound allows for 2^4 = 16 levels of amplitude. This means that the sound can represent 16 different discrete values of amplitude.
1. A single bit can represent two different values, 0 and 1. Then simply take the largest of those two possible values, 1, and that's your answer.
8
one bit in two output states true or false
An 8-bit sound allows for 256 different levels of amplitude values. This means that the amplitude range can be divided into 256 discrete steps, providing a level of precision in representing sound intensity.
It can have 0 to 1 It can have 0 to 1
An N-bit integer holds 2N different values.For an unsigned integer, the range of values is 0..2N-1 thus.For a signed integer using 2s complement, the range is -2N-1..+2N-1-1.Therefore, the largest positive number that can be stored using 8 bits is 255.