Two: '0' or '1'
An 8-bit binary number consists of 8 symbols, each of which can be either a 0 or a 1. This means that there are two possible values for each bit. Therefore, an 8-bit binary number can represent a total of (2^8 = 256) different values.
A 4-bit binary number can represent (2^4 = 16) different values. This range includes all combinations of 0s and 1s that can be formed with four bits, ranging from 0000 (0 in decimal) to 1111 (15 in decimal). Thus, the values it can represent are 0 through 15.
Well, honey, in an 8-bit register, you can store a total of 256 different binary values. That's because each bit can be either a 0 or a 1, giving you 2 options per bit. And when you have 8 bits, you just multiply 2 by itself 8 times to get 256. Math doesn't lie, darling.
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Two: '0' or '1'
0 o 1
24, or 16 (0 through 15) One binary digit (bit) can have 21 values (0 or 1). Two bits can have 22 values. Three bits can have 23 values. A five-bit number can have 25 values... and so on...
A 128-bit register can store 2 128th (over 3.40 × 10 38th) different values. The range of integer values that can be stored in 128 bits depends on the integer representation used.
An 8-bit binary number consists of 8 symbols, each of which can be either a 0 or a 1. This means that there are two possible values for each bit. Therefore, an 8-bit binary number can represent a total of (2^8 = 256) different values.
A 4-bit sound allows for 2^4 = 16 levels of amplitude. This means that the sound can represent 16 different discrete values of amplitude.
Well, honey, in an 8-bit register, you can store a total of 256 different binary values. That's because each bit can be either a 0 or a 1, giving you 2 options per bit. And when you have 8 bits, you just multiply 2 by itself 8 times to get 256. Math doesn't lie, darling.
1. A single bit can represent two different values, 0 and 1. Then simply take the largest of those two possible values, 1, and that's your answer.
It can have 0 to 1 It can have 0 to 1
An 8-bit sound allows for 256 different levels of amplitude values. This means that the amplitude range can be divided into 256 discrete steps, providing a level of precision in representing sound intensity.
The number of different bit strings of length 7 can be calculated using the formula 2^n, where n is the length of the bit string. In this case, with a length of 7, there are 2^7 = 128 different bit strings possible. This is because each bit in the string can have 2 possible values (0 or 1), and there are 7 bits in total.
65,536