The divisors of 23 are: 1, 23.
23 divide 3974
320 has 14 divisors.
24 of them.
276 = 2^2*3*23 So the divisors of 276 are 2^a*3^b*23^c where 0<=a<=2, 0<=b<=1 and 0<=c<=1. That is, 1, 2, 3, 4, 6, 12, 23, 46, 69, 92, 138 and 276.
23 is a prime number. It has two divisors.
The divisors of 23 are: 1, 23.
23 divide 3974
12 has six divisors.
136 has eight divisors.
100,000 has 36 divisors.
84 has 12 divisors.
600 has 24 divisors.
2,835 has 20 divisors.
320 has 14 divisors.
Least number with exactly n even divisors 1 -> 0 divisor 2 -> 1 divisor 4 -> 2 divisors = 22 8 -> 3 divisors = 23 12 -> 4 divisors = 22x3 32 -> 5 divisors = 24
23 is a prime number so its only integral divisors are 1 and 23.