How many feet does a pebble fall in ten seconds?

Answer 1

To determine how far a pebble falls in ten seconds, we can use the formula for the distance of free fall, which is (d = \frac{1}{2}gt^2), where (g) is the acceleration due to gravity (approximately 32 feet per second squared) and (t) is the time in seconds. Plugging in the values, we get (d = \frac{1}{2} \times 32 \times (10^2) = 1600) feet. Therefore, a pebble falls approximately 1,600 feet in ten seconds.