If the rock falls at 96 feet per second then multiply that by two to find out how far the rock traveled in two seconds which is 192 feet. Subtract 192 from 640 and the answer is 448. Therefore, the rock is 448 feet high after two seconds.
45
It depends how densely it is distributed.
29.4
Volume = (84) x (1/6) = 14 cubic feet = 0.52 cubic yard
whats the weight and shape of the rock it depends on that >:(
:.)
d = 16t² t = 1 s → d = 16 × 1² = 16 × 1 = 16 ft
If the rock falls at 96 feet per second then multiply that by two to find out how far the rock traveled in two seconds which is 192 feet. Subtract 192 from 640 and the answer is 448. Therefore, the rock is 448 feet high after two seconds.
After 3 seconds, a rock dropped from a great height will fall 44.1 meters neglecting air resistance. This distance can be calculated using the equation (d = 0.5 \times g \times t^2), where (d) is the distance fallen, (g) is the acceleration due to gravity (approximately 9.81 m/s^2), and (t) is the time in seconds.
The speed of the rock after 5 seconds of free fall would not be 100. The speed of an object in free fall increases by 9.8 m/s every second. After 5 seconds, the speed of the rock would be 49 m/s (approximately), assuming no air resistance.
Well, you will need to solve the function for x. Fill in the blanks and do what is needed to get your answer.
I got 182098000 seconds
45
depends on the mass of the stone, the shape of the stone, and the height dropped from. sorry dude.
The rock is 6 and a half foot
In order to come up with an answer, we have to impose a couple of rules: 1). we're trying this on the earth 2). we're ignoring the effects of air 3). it's not moving at the beginning of the 5 seconds ... that's when you drop it from your hand Then the rock falls 400 ft in five seconds. What's really interesting is that it doesn't matter how much it weighs. ALL rocks fall the same distance in 5 seconds.