whats the weight and shape of the rock it depends on that >:(
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Well the average terminal velocity ofr an average sized jumper is 120mph. I fall at 120mph and fall 10,000 feet in 45/50 seconds so I guess about 213 feet per second.
About 18.7736250 seconds assuming that air friction is zero. I used a graphing calculator.. I'm not sure about what the formula for figuring this out is.
Because this is a free fall questions, the equation d=1/2gt² can be used. Gravity is a given, 9.8 m/s² and the time is your 15 seconds of free fall. d=1/2(9.8m/s²)(15s)²= 1,102.5m. To find feet multiply 3.28084 to answer because that is how many feet are in a meter.
1 second, since all objects fall at 16 feet per second.
H = 1/2 G T2 = 1/2 (32.2) (1.5)2 = 36.23 feet