whats the weight and shape of the rock it depends on that >:(
Well the average terminal velocity ofr an average sized jumper is 120mph. I fall at 120mph and fall 10,000 feet in 45/50 seconds so I guess about 213 feet per second.
About 18.7736250 seconds assuming that air friction is zero. I used a graphing calculator.. I'm not sure about what the formula for figuring this out is.
Because this is a free fall questions, the equation d=1/2gt² can be used. Gravity is a given, 9.8 m/s² and the time is your 15 seconds of free fall. d=1/2(9.8m/s²)(15s)²= 1,102.5m. To find feet multiply 3.28084 to answer because that is how many feet are in a meter.
To determine how far a pebble falls in ten seconds, we can use the formula for the distance of free fall, which is (d = \frac{1}{2}gt^2), where (g) is the acceleration due to gravity (approximately 32 feet per second squared) and (t) is the time in seconds. Plugging in the values, we get (d = \frac{1}{2} \times 32 \times (10^2) = 1600) feet. Therefore, a pebble falls approximately 1,600 feet in ten seconds.
H = 1/2 G T2 = 1/2 (32.2) (1.5)2 = 36.23 feet
If we assume the time it takes for the ball to stop is directly proportional to the height it is dropped from, we can set up a proportion based on the given information. From the given data, we have the ratio of time to height as 11/1 = 25/2. Therefore, if we continue this ratio, the time it would take to stop if dropped from 3 feet would be 55 seconds.
Ignoring air resistance, that would be about 145 feet.
Well the average terminal velocity ofr an average sized jumper is 120mph. I fall at 120mph and fall 10,000 feet in 45/50 seconds so I guess about 213 feet per second.
About 18.7736250 seconds assuming that air friction is zero. I used a graphing calculator.. I'm not sure about what the formula for figuring this out is.
Because this is a free fall questions, the equation d=1/2gt² can be used. Gravity is a given, 9.8 m/s² and the time is your 15 seconds of free fall. d=1/2(9.8m/s²)(15s)²= 1,102.5m. To find feet multiply 3.28084 to answer because that is how many feet are in a meter.
There are no seconds in feet. Feet is a unit of measurement while seconds is a unit of Time.
It went off within the minute.
To determine how far a pebble falls in ten seconds, we can use the formula for the distance of free fall, which is (d = \frac{1}{2}gt^2), where (g) is the acceleration due to gravity (approximately 32 feet per second squared) and (t) is the time in seconds. Plugging in the values, we get (d = \frac{1}{2} \times 32 \times (10^2) = 1600) feet. Therefore, a pebble falls approximately 1,600 feet in ten seconds.
The time it takes for a volleyball to hit the ground when dropped from a height depends on the height it falls from. Using the formula for free fall ( t = \sqrt{\frac{2h}{g}} ), where ( h ) is the height in meters and ( g ) is the acceleration due to gravity (approximately ( 9.81 , m/s^2 )), you can calculate the time. For example, if dropped from 2 meters, it would take about 0.64 seconds to hit the ground.
H = 1/2 G T2 = 1/2 (32.2) (1.5)2 = 36.23 feet
Zero
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