Is this a trick question?
3456
3465
3546
3564
3645
3654
4356
4365
4536
4563
4635
4653
5346
5364
5436
5463
5634
5643
6345
6354
6435
6453
6534
6543
64 if repetition is allowed.24 if repetition is not allowed.
If repetition of digits isn't allowed, then no13-digit sequencescan be formed from only 5 digits.
There are 10 to the 10th power possibilities of ISBN numbers if d represents a digit from 0 to 9 and repetition of digits are allowed. That means there are 10,000,000,000 ISBN numbers possible.
10^7 if the repetition of digits is allowed. 9*8*7*6*5*4*3 , if the repetition of digits is not allowed.
125
64 if repetition is allowed.24 if repetition is not allowed.
If repetition of digits is allowed, then 56 can.If repetition of digits is not allowed, then only 18 can.
If repetition of digits isn't allowed, then no13-digit sequencescan be formed from only 5 digits.
24 three digit numbers if repetition of digits is not allowed. 4P3 = 24.If repetition of digits is allowed then we have:For 3 repetitions, 4 three digit numbers.For 2 repetitions, 36 three digit numbers.So we have a total of 64 three digit numbers if repetition of digits is allowed.
-123456787
There are 10 to the 10th power possibilities of ISBN numbers if d represents a digit from 0 to 9 and repetition of digits are allowed. That means there are 10,000,000,000 ISBN numbers possible.
10^7 if the repetition of digits is allowed. 9*8*7*6*5*4*3 , if the repetition of digits is not allowed.
125
290
-4
125 There are five choices for each of the three digits (since repetition is allowed). So there are 5*5*5=125 combinations.
Possible solutions - using your rules are:- 11,13,17,31,33,37,71,73 &77