64
Any number that ends with 5 or 0 except 0 itself is divisble by 5
There are 9 x 10 x 10 x 10, or 9000 four-digit number that can be formed if the leading digit cannot be zero.
24 ways
There is 90 four digit palindromes.
64
Any number that ends with 5 or 0 except 0 itself is divisble by 5
Four of them.
How many four digit combinations can be made from the number nine? Example, 1+1+2+5=9.
There are 9 x 10 x 10 x 10, or 9000 four-digit number that can be formed if the leading digit cannot be zero.
The number is a 13-digit number.
24 ways
1234
There is 90 four digit palindromes.
Absolutely ! There are many solutions - the lowest is... 1999-999=1000 *Side note* Actually, the solution when looking for the lowest value of the term that still gives you a four-digit differance, has to be found in the answer of 1100 - 100 = 1000, since 100 is the - using your word- "lowest" value of a three digit-number, as well as 1000 being the "lowest" four-digit number.
24
The answer is 3,584. The first digit of the four-digit number can be one of seven figures: 1,2,4,5,7,8 or 9 (if it is 0, then you don't have a four-digit number!) Each of the remaining digits can be one of eight figures: 1,2,4,5,7,8,9 or 0. The number of possible combinations is therefore 7 x 8 x 8 x 8 = 3,584.