120 combinations using each digit once per combination. There are 625 combinations if you can repeat the digits.
1,000. The list looks just like the counting numbers from 000 to 999 .
To calculate the number of 3-digit combinations using numbers 1-6, including 1 and 6, we need to consider the total number of options for each digit. Since we are including 1 and 6, there are 6 options for the hundreds place (1-6), 6 options for the tens place (1-6), and 6 options for the ones place (1-6). Therefore, the total number of 3-digit combinations is 6 x 6 x 6 = 216.
There are 15, and they are:1234 1235 1236 1245 1246 1256 1345 1346 1356 1456 2345 2346 2356 2456 3456.
if its not alphanumeric, 999999 variations
Number of 7 digit combinations out of the 10 one-digit numbers = 120.
There are 840 4-digit combinations without repeating any digit in the combinations.
120 combinations using each digit once per combination. There are 625 combinations if you can repeat the digits.
9
-8
There cannot be such a number.
It depends. If you can only use each number once, there are 720 combinations. If you can use numbers multiple times, then there are 1000 combinations, by using all numbers from 000 to 999.
It is: 9C7 = 36
10,000
15
it depends on which 8 numbers your talking about
If there are no restrictions on duplicated numbers or other patterns of numbers then there are 10 ways of selecting the first digit and also 10 ways of selecting the second digit. The number of combinations is therefore 10 x 10 = 100.