1 acre = 43,560 square feet
1 cubic foot = 1,728 cubic inches
231 cubic inches = 1 US gallon
Volume = (10 acres) x (15 ft) = (435,600) x (15) = 6,534,000 cubic feet
= 48,877,714.3 US gallons (rounded)
1 acre = 43560 sq.feet. 1 foot deep water over an acre is 43560 cubic feet, which is 325851.4 gallons in 1 foot deep. If it is 1 inch deep (1/12 foot) then it is 27154.3 gallons in 1 inch deep.
1.6042 square feet (rounded)
alot! 1,234,345.
43560x7x7.48052=2,280,960.1584
To find the volume in cubic feet of 1 acre of land that is 3 feet deep, first note that 1 acre is equal to 43,560 square feet. Multiplying the area by the depth gives: 43,560 sq ft × 3 ft = 130,680 cubic feet. Therefore, there are 130,680 cubic feet in 1 acre of land that is 3 feet deep.
A 1000 acre lake that is 7 feet deep (uniformly) will have 7000 acre feet of water in it. An acre foot is an acre of water one foot deep, and the unit is used to measure reservoir water capacity. The conversion factor is that one acre foot equals about 325,851.5 gallons. The lake in question is holding 7000 times 325,851.5 gallons of water.
1 US gallon = 0.00000307 acre feet, approx.
If the pond is uniformly 6-feet deep it would contain about 1,955,109 gallons of water.
1 acre = 43560 sq.feet. 1 foot deep water over an acre is 43560 cubic feet, which is 325851.4 gallons in 1 foot deep. If it is 1 inch deep (1/12 foot) then it is 27154.3 gallons in 1 inch deep.
Due to lack of information to the contrary, we will assume that the lake is 18 feet deep all around.The first thing to do is convert 56,000 acres into square feet, so that the various measurements are all in the same units.An acre is 43,560 square feet, so 56,000 acres = 2,439,360,000 square feet.That area to a depth of 18 feet = 43,908,480,000 cubic feet.* An imperial gallon = 277.420 cubic inches, or 0.160543981 cubic feet * 43,908,480,000 / 0.160543981 = 273,498,138,806 gallons (rounded to the nearest gallon)* A US gallon = 231 cubic inches = 0.133680555 cubic feet * 43,908,480,000 / 0.133680555 = 328,458,241,365 gallons (rounded to the nearest gallon)
1.6042 square feet (rounded)
1 acre is 6,272,640 square inches. Since you want to cover it one inch deep you need 6,272,640 cubic inches of water. There are 231 cubic inches in a gallon. So divide 6,272,640 by 231 and you get 27,154.2857 gallons! HOWEVER: If you want to save water, consider this: When water freezes, it increases in volume about 9%. So if you used ICE to cover your acre and only needed the ice to be 1 inch deep, you could use 9% less water to start with! (I'll let you do the math on that.) Ice is still water, so unless you are asked to use LIQUID water this question has 2 answers.
alot! 1,234,345.
43560x7x7.48052=2,280,960.1584
Approximately 977,553 gallons of water.
To calculate the volume of water in a 150-acre lake that is 20 feet deep, first convert acres to square feet (1 acre = 43,560 square feet). Therefore, 150 acres is 6,534,000 square feet. The volume in cubic feet is then 6,534,000 square feet multiplied by 20 feet, equaling 130,680,000 cubic feet. Since there are approximately 7.48 gallons in a cubic foot, the total volume in gallons is about 975,840,000 gallons.
Volume = (area of the base) times (depth)1 acre = 43,560 square ft1 acre, 1-ft deep = 1 "acre-foot" = 43,560 x 1 = 43,560 cubic feet = 1,613 1/3 cubic yardsAlso 325,851.4 gallons (rounded)