0
How many gallons each of 25 percent alcohol and 35 percent alcohol should be mixed to obtain 20 gallons of 32 percent alcohol?
Wiki User
∙ 11y ago
The question is best solved using basic algebra.
You need 20 gallons of 32% alcohol. This will contain 0.32*20 = 6.4 gallons of pure alcohol.
Now suppose you have X gallons of 25% alcohol in the mixture. That contains 0.25X gallons of pure alcohol.
Also, since you have 20 gallons in total, you must have 20-X gallons of the 35% alcohol. This will contain 0.35*(20-X) = 7 - 0.35X gallons of pure alcohol.
Then, the total amount of pure alcohol is 0.25X + 7 - 0.35X = 7 - 0.1X gallons.
So you have 7 - 0.1X = 6.4
or 0.6 = 0.1X or X = 6.
So the answer is 6 gallons of 25% alcohol and 14 gallons of the stronger stuff!
Wiki User
∙ 11y ago
Add your answer:
Earn +20 pts
How much water should be added to 1 gallon of pure antifreeze to obtain a solution that is 60 percent antifreeze?
2 gallons.
How much water should be added to 1 gallon of pure antifreeze to obtain a solution that is 80 percent antifreeze?
0.25 gallons of water (or 1 quart)
How many ml of water should be added to 95 percent ethyl alcohol to make 1 liter of a 30 percent ethyl alcohol solution?
684 ml
How much water should be added to 3 gallons of pure acid in order to obtain the 15 acid solution?
You need 17 gallons for a 15% volume/volume mixture.
How much pure acid should be mixed with 5 gallons of 70 percent acid solution in order to get a 90 percent acid solution?
x=45
What fraction of 10 percent alcohol should be mixed with 70 percent alcohol to obtain 50 percent alcohol?
2/3 of 70% and 1/3 of 10%
How much water should be added to 1 gallon of pure antifreeze to obtain a solution that is 60 percent antifreeze?
2 gallons.
How much water should be mixed to 12ml of alcohol to obtain a 12 percent of alcohol solution?
To obtain a 12% alcohol solution, you would need to mix 12ml of alcohol with 48ml of water. This would give you a total volume of 60ml, with 12% of it being alcohol.
How much water should be added to 1 gallon of pure antifreeze to obtain a solution that is 80 percent antifreeze?
0.25 gallons of water (or 1 quart)
How many gallons of 30 percent antifreeze should be mixed with 10 percent gallons of 93 percent antifreeze to obtain a 65 percent antifreeze mixture?
Suppose there are G gallons of the 30% mix. Then G gallons of 30% contain 0.3*G gallons of the active ingredient. Also 10% gallons = 0.1 gallons of 93% contain 0.093 gallons of the active ingredient. Therefore, the total volume is G+0.1 gallons which contains 0.3*G + 0.093 gallons of the active ingredient. So its strength is (0.3*G + 0.393)/(G+0.1) which is 65% or 0.65 Thus 0.3*G + 0.093 = 0.65*G + 0.065 So that 0.028 = 0.35G Or G = 0.08 gallons
How much 50 percent antifreeze solution and 40 percent antifreeze solution should be combined to give 50 gallons of 46 percent antifreeze solution?
How much 50 percent antifreeze solution and 40 percent antifreeze solution should be combined to give 50 gallons of 46 percent antifreeze solution?
How many ml of water should be added to 95 percent ethyl alcohol to make 1 liter of a 30 percent ethyl alcohol solution?
684 ml
How much water should be added to 3 gallons of pure acid in order to obtain the 15 acid solution?
You need 17 gallons for a 15% volume/volume mixture.
How much pure acid should be mixed with 5 gallons of 70 percent acid solution in order to get a 90 percent acid solution?
x=45
How many liters of a 20 percent solution of acid should be added to 10 liters of a 30 percent solution of acid to obtain a 25 percent solution?
10 liters.
How much water should be added to four liters of 75 percent alcohol to make a mixture of 30 percent alcohol?
There are 3 litres of alcohol in your starting mixture of 4 litres. If you add 6 litres of water you will have 3 litres of alcohol in a total of 10 litres. This is the required strength.
How much pure acid should be mixed with 6 gallons of a 50 percent acid solution in order to get an 80 percent acid solution?
50% acid in a 6 gallon solution means that 3 gallons are acid. 9 gallons more acid will give you a total of 12 gallons of acid in a 15 gallon solution. 12 is 80% of 15.
