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How many liters of a 20 percent solution of saline should a nurse mix with 10 liters of a 50 percent solution to obtain a mixture that is 40 percent saline?
Let x = the amount of 20% solution Let x + 10 = the amount of the final solution. So we have: (.20)x + (.50)(10) = (.40)(x + 10) .20x + 5 = .40x + 4 .20x = 1 x = 5 liters of 20% solution of saline.
How many ml of water should be added to 95 percent ethyl alcohol to make 1 liter of a 30 percent ethyl alcohol solution?
684 ml
In what proportion should 95 percent percent alcohol be mised with 30 percent percent alcohol to make 70 percent percent?
x = volume of 95% y = volume of 30% so (x+y) is volume of 70% 0.95 x + 0.30 y = 0.70(x+y) 0.95 x + 0.30 y = 0.70x + 0.70y 0.25x = 0.40y x/y = 0.40/0.25 = 8/5 for every 8 volumes of 95% mix in 5 volumes of 30%the volumes can be ml, liters, cups, pints etc.
How many gallons each of 25 percent alcohol and 35 percent alcohol should be mixed to obtain 20 gallons of 32 percent alcohol?
The question is best solved using basic algebra. You need 20 gallons of 32% alcohol. This will contain 0.32*20 = 6.4 gallons of pure alcohol. Now suppose you have X gallons of 25% alcohol in the mixture. That contains 0.25X gallons of pure alcohol. Also, since you have 20 gallons in total, you must have 20-X gallons of the 35% alcohol. This will contain 0.35*(20-X) = 7 - 0.35X gallons of pure alcohol. Then, the total amount of pure alcohol is 0.25X + 7 - 0.35X = 7 - 0.1X gallons. So you have 7 - 0.1X = 6.4 or 0.6 = 0.1X or X = 6. So the answer is 6 gallons of 25% alcohol and 14 gallons of the stronger stuff!
How many ounces of the 50 percent alcohol solution should be mixed with the 1 percent alcohol solution to make 8 oz of the 20 percent alcohol solution?
Let x = ounces of 50% solution, and y = ounces of 1% solution. So that we have: 0.5x + 0.01y = 8(0.2) which is a linear equation in two variables, meaning there are infinitely many choices of mixing those solutions.
A mixture of 40 liters of milk and water contains 10 percent water How much water should be added to this so that water may be 20 percent in the new mixture?
If you're talking about 10 liters of water and not percent, then 10 liters. But then you'll have 60 liters of mixture. It would be 2/5 or 0.4 x 50 = 20 this would make a mix of 20/50. Waterman
How many liters of a 20 percent solution of acid should be added to 10 liters of a 30 percent solution of acid to obtain a 25 percent solution?
10 liters.
What fraction of 10 percent alcohol should be mixed with 70 percent alcohol to obtain 50 percent alcohol?
2/3 of 70% and 1/3 of 10%
How many liters of a 20 percent solution of saline should a nurse mix with 10 liters of a 50 percent solution to obtain a mixture that is 40 percent saline?
Let x = the amount of 20% solution Let x + 10 = the amount of the final solution. So we have: (.20)x + (.50)(10) = (.40)(x + 10) .20x + 5 = .40x + 4 .20x = 1 x = 5 liters of 20% solution of saline.
How many ml of water should be added to 95 percent ethyl alcohol to make 1 liter of a 30 percent ethyl alcohol solution?
684 ml
In what proportion should 95 percent percent alcohol be mised with 30 percent percent alcohol to make 70 percent percent?
x = volume of 95% y = volume of 30% so (x+y) is volume of 70% 0.95 x + 0.30 y = 0.70(x+y) 0.95 x + 0.30 y = 0.70x + 0.70y 0.25x = 0.40y x/y = 0.40/0.25 = 8/5 for every 8 volumes of 95% mix in 5 volumes of 30%the volumes can be ml, liters, cups, pints etc.
How many gallons each of 25 percent alcohol and 35 percent alcohol should be mixed to obtain 20 gallons of 32 percent alcohol?
The question is best solved using basic algebra. You need 20 gallons of 32% alcohol. This will contain 0.32*20 = 6.4 gallons of pure alcohol. Now suppose you have X gallons of 25% alcohol in the mixture. That contains 0.25X gallons of pure alcohol. Also, since you have 20 gallons in total, you must have 20-X gallons of the 35% alcohol. This will contain 0.35*(20-X) = 7 - 0.35X gallons of pure alcohol. Then, the total amount of pure alcohol is 0.25X + 7 - 0.35X = 7 - 0.1X gallons. So you have 7 - 0.1X = 6.4 or 0.6 = 0.1X or X = 6. So the answer is 6 gallons of 25% alcohol and 14 gallons of the stronger stuff!
How much water should be mixed to 12ml of alcohol to obtain a 12 percent of alcohol solution?
To obtain a 12% alcohol solution, you would need to mix 12ml of alcohol with 48ml of water. This would give you a total volume of 60ml, with 12% of it being alcohol.
A chemist has one solution which is 50 percent acid and a second solution which is 25 percent acid how much of each should be mixed to make a 10 liters of a 40 percent acid solution?
6 litres of 50% + 4 litres of 25%
What mixture will thaw ice on a car and what is it made of?
Most de-icer sprays for windshields and car locks contain methanol (methyl alcohol) and propylene glycol (antifreeze). These can be harmful to humans and pets, so should be used sparingly and wiped up after use.
What percent of alcohol do the human body needs?
You don't need alcohol at all. It's not necessary.
How do you distill hand sanitizer in order to make edible alcohol?
Wikipedia has an article on Alcohol Rubs here: http://en.wikipedia.org/wiki/Hand_sanitizer They typically use ethanol (standard drinking alcohol mixed with something to render it undrinkable) or isopropanol ("rubbing alcohol" which is poisonous — not in a good way — if swallowed). A concentration of 60-70 percent is needed. Standard rubbing alcohol should do the trick, as would a 120+ proof liquor, although both will dry out your skin. You could mix in a small amount of glycerine for moisturizing, and possibly a thickener, but you risk diluting the alcohol to where the mixture is no longer effective. A mixture of nine parts 70% rubbing alcohol to one part glycerine should give you a good (but runny) substitute at a lower price.
