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66. Each of the 12 members shook hands with the 11 other people. That would make 12*11 hand shakes. BUT, the A shaking B's hand is the same event as B shaking A's hand so all these handshakes are double-counted. The actual number is half that ie 33. If you are more familiar with combinatorial mathematics, the answer is the number of combinations of two obejects from 12, which is 12C2 = 12*11/(2*1)
If each person is shaking with only one hand, then the answer is seven. If they are shaking with both hands, then the answer is 14.
20 hand shakes would take place. Here's how: 1234567 23456 34567 4567 567 67 7 And a person can't shake his own hand or someones hands twice
Each boy shook hands 11 times which would be 132 handshakes but two boys were involved in each therefore 66. Other method: Boy 1 shakes with 11 others, boy 2 has already shaken with boy 1 so has to shake with 10 others and so on. 11 + 10 + 9 ....+ 3 + 2 + 1 = 66
The question is ambiguous:If each girl shakes one other person's hand once, then there are seven (7) handshakes.If each girl shakes each other girl's hand once, then there are 7 x 6 x 0.5 = 21 handshakes (each girl x each other girl x cancelling out the doubles).Another way to look at this one:If each girl shakes each of the other girl's hand once, there would be 42 shakes (each girl shakes 6 hands, times 7 girls, an assupmtion is made that each girl is not shaking her own hands, you can't tell much from the question so assuming ensues)