To determine how many W-inch sections you can get from a 9-foot piece of plywood, first convert the length of the plywood into inches. Since 9 feet equals 108 inches, you would divide 108 inches by W inches. The formula would be: Number of sections = 108 / W. The result will give you the total number of W-inch sections you can cut from the 9-foot plywood.
Let the width be ( w ) inches and the height be ( h = w + 6 ) inches. The area of the storm window can be expressed as ( w \times h = 315 ) square inches. Substituting for ( h ), we have ( w(w + 6) = 315 ). Solving this gives the width ( w \approx 15 ) inches and height ( h \approx 21 ) inches.
The answer depends on what sort of triangle: right angled, equilateral, isosceles or scalene.
Suppose width = W inches. Then length, L = W + 2.5 inches. Area = L*W = (W + 2.5)*W which is 37.5 sq inches. Therefore W2 + 2.5W - 37.5 = 0 Multiplying by 2, to get rid of the fraction, 2W2 + 5W - 75 = 0 (2W +15)(W - 5) = 0 So W = -73.5 or W = 5 Since W is a length, it cannot be negative, so W = 5 inches Then L = W + 2.5 = 7.5 inches Therefore, the perimeter is 2*(L+W) = 2*(7.5 + 5) = 2*12.5 = 25 inches.
Total surface area = 2*(H*L + L*W + W*H) 308 = 2*(6*4 + 4*W + W*6) that is 154 = 24 + 4W + 6W or 130 = 10 W so that W = 13 inches.
To determine how many W-inch sections you can get from a 9-foot piece of plywood, first convert the length of the plywood into inches. Since 9 feet equals 108 inches, you would divide 108 inches by W inches. The formula would be: Number of sections = 108 / W. The result will give you the total number of W-inch sections you can cut from the 9-foot plywood.
(6 + w) = length w = width (6 + w)(w) = 40 square inches w squared + 6w = 40 w = 4 inches and the length must be equal to 10 inches
Let the width be ( w ) inches and the height be ( h = w + 6 ) inches. The area of the storm window can be expressed as ( w \times h = 315 ) square inches. Substituting for ( h ), we have ( w(w + 6) = 315 ). Solving this gives the width ( w \approx 15 ) inches and height ( h \approx 21 ) inches.
P = 2(L + W) = 236 L + W = 118 W + 64 + W = 118 (since L = W + 64) 2W = 54 W = 27 inches and then L = W + 64 = 91 inches
32 = L + W + L + W 32 = 10 + W + 10 + W 12 = W + W 6 = W
The answer depends on what sort of triangle: right angled, equilateral, isosceles or scalene.
There are infinitely many options. Let L ≥ 28.2843 [= sqrt(800] inches. and let W = 800/L inches. Then L=W = L * (800/L) = 800 sq inches. Since L can have by 28.2843 in or ANY larger value, there are infinitely many possibilities. And each one of them gives a valid solution.
To determine the volume in cubic inches, you multiply the height (H), length (L), and width (W) together using the formula: Volume = H × L × W. The resulting product gives you the volume in cubic inches. Make sure that all dimensions are measured in inches before performing the calculation.
Suppose width = W inches. Then length, L = W + 2.5 inches. Area = L*W = (W + 2.5)*W which is 37.5 sq inches. Therefore W2 + 2.5W - 37.5 = 0 Multiplying by 2, to get rid of the fraction, 2W2 + 5W - 75 = 0 (2W +15)(W - 5) = 0 So W = -73.5 or W = 5 Since W is a length, it cannot be negative, so W = 5 inches Then L = W + 2.5 = 7.5 inches Therefore, the perimeter is 2*(L+W) = 2*(7.5 + 5) = 2*12.5 = 25 inches.
Total surface area = 2*(H*L + L*W + W*H) 308 = 2*(6*4 + 4*W + W*6) that is 154 = 24 + 4W + 6W or 130 = 10 W so that W = 13 inches.
38 inches = perimeter 2*(w+l); 88 sq inches = Area (w*l)
l = 2*w - 3