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How Many W Inch Sections Can You Get Out Of The 9 Foot Piece Of Plywood?
To determine how many W-inch sections you can get from a 9-foot piece of plywood, first convert the length of the plywood into inches. Since 9 feet equals 108 inches, you would divide 108 inches by W inches. The formula would be: Number of sections = 108 / W. The result will give you the total number of W-inch sections you can cut from the 9-foot plywood.
If a storm window has an area of 315 square inches what are the dimensions if the window is 6 inches higher than it is wide (w x h)?
Let the width be ( w ) inches and the height be ( h = w + 6 ) inches. The area of the storm window can be expressed as ( w \times h = 315 ) square inches. Substituting for ( h ), we have ( w(w + 6) = 315 ). Solving this gives the width ( w \approx 15 ) inches and height ( h \approx 21 ) inches.
If a storm window has an area of 448 square inches what are the dimensions if the window is 12 inches higher than it is wide (w x h)?
Let the width of the window be ( w ) inches and the height be ( h = w + 12 ) inches. The area of the window can be expressed as ( w \times h = 448 ) square inches. Substituting ( h ) gives the equation ( w(w + 12) = 448 ). Solving this quadratic equation, we find the dimensions to be ( w = 16 ) inches and ( h = 28 ) inches.
What are the length and width of a rectangular traffic sign if the length exceeds the width by 3 inches and the perimeter is 162 inches?
Let the width be ( w ) inches. Then the length is ( w + 3 ) inches. The perimeter of a rectangle is given by the formula ( P = 2(l + w) ). Setting up the equation, we have ( 2(w + 3 + w) = 162 ), which simplifies to ( 4w + 6 = 162 ). Solving for ( w ), we find ( w = 39 ) inches, and thus the length is ( 42 ) inches. Therefore, the dimensions of the sign are 39 inches in width and 42 inches in length.
What is the area of a triangular prism if the height is W inches the length W inches and the base W inches?
The answer depends on what sort of triangle: right angled, equilateral, isosceles or scalene.
How Many W Inch Sections Can You Get Out Of The 9 Foot Piece Of Plywood?
To determine how many W-inch sections you can get from a 9-foot piece of plywood, first convert the length of the plywood into inches. Since 9 feet equals 108 inches, you would divide 108 inches by W inches. The formula would be: Number of sections = 108 / W. The result will give you the total number of W-inch sections you can cut from the 9-foot plywood.
If the area of a rectangle is 40 square inches and the length is 6 inches more than the width what is the length and the width of the rectangle?
(6 + w) = length w = width (6 + w)(w) = 40 square inches w squared + 6w = 40 w = 4 inches and the length must be equal to 10 inches
If a storm window has an area of 315 square inches what are the dimensions if the window is 6 inches higher than it is wide (w x h)?
Let the width be ( w ) inches and the height be ( h = w + 6 ) inches. The area of the storm window can be expressed as ( w \times h = 315 ) square inches. Substituting for ( h ), we have ( w(w + 6) = 315 ). Solving this gives the width ( w \approx 15 ) inches and height ( h \approx 21 ) inches.
The perimeter of a rectangle is 236 inches The length exceeds the width by 64 inches What is the length and width?
P = 2(L + W) = 236 L + W = 118 W + 64 + W = 118 (since L = W + 64) 2W = 54 W = 27 inches and then L = W + 64 = 91 inches
If a storm window has an area of 448 square inches what are the dimensions if the window is 12 inches higher than it is wide (w x h)?
Let the width of the window be ( w ) inches and the height be ( h = w + 12 ) inches. The area of the window can be expressed as ( w \times h = 448 ) square inches. Substituting ( h ) gives the equation ( w(w + 12) = 448 ). Solving this quadratic equation, we find the dimensions to be ( w = 16 ) inches and ( h = 28 ) inches.
The perimeter of a rectangle is 32 inches Its length is 10 inches What is its width?
32 = L + W + L + W 32 = 10 + W + 10 + W 12 = W + W 6 = W
What are the length and width of a rectangular traffic sign if the length exceeds the width by 3 inches and the perimeter is 162 inches?
Let the width be ( w ) inches. Then the length is ( w + 3 ) inches. The perimeter of a rectangle is given by the formula ( P = 2(l + w) ). Setting up the equation, we have ( 2(w + 3 + w) = 162 ), which simplifies to ( 4w + 6 = 162 ). Solving for ( w ), we find ( w = 39 ) inches, and thus the length is ( 42 ) inches. Therefore, the dimensions of the sign are 39 inches in width and 42 inches in length.
What is the area of a triangular prism if the height is W inches the length W inches and the base W inches?
The answer depends on what sort of triangle: right angled, equilateral, isosceles or scalene.
What are the dimensions of 800 square inches and under L x W equals IN 2?
There are infinitely many options. Let L ≥ 28.2843 [= sqrt(800] inches. and let W = 800/L inches. Then L=W = L * (800/L) = 800 sq inches. Since L can have by 28.2843 in or ANY larger value, there are infinitely many possibilities. And each one of them gives a valid solution.
If a storm window has an area of 448 square inches what are the dimensions of the window is 12 inches higher than it is wide?
Let the width of the storm window be ( w ) inches. Then the height would be ( w + 12 ) inches. The area of the window can be expressed as ( w(w + 12) = 448 ). Solving the equation ( w^2 + 12w - 448 = 0 ) gives ( w = 16 ) inches (width) and ( h = 28 ) inches (height), so the dimensions of the window are 16 inches wide and 28 inches high.
How many cubic inches is H x L x W?
To determine the volume in cubic inches, you multiply the height (H), length (L), and width (W) together using the formula: Volume = H × L × W. The resulting product gives you the volume in cubic inches. Make sure that all dimensions are measured in inches before performing the calculation.
What is the perimeter of a rectangle whose length is 2.5 greater than its width with an area of 37.5 square inches show work?
Suppose width = W inches. Then length, L = W + 2.5 inches. Area = L*W = (W + 2.5)*W which is 37.5 sq inches. Therefore W2 + 2.5W - 37.5 = 0 Multiplying by 2, to get rid of the fraction, 2W2 + 5W - 75 = 0 (2W +15)(W - 5) = 0 So W = -73.5 or W = 5 Since W is a length, it cannot be negative, so W = 5 inches Then L = W + 2.5 = 7.5 inches Therefore, the perimeter is 2*(L+W) = 2*(7.5 + 5) = 2*12.5 = 25 inches.
