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If a storm window has an area of 315 square inches what are the dimensions if the window is 6 inches higher than it is wide (w x h)?
Let the width be ( w ) inches and the height be ( h = w + 6 ) inches. The area of the storm window can be expressed as ( w \times h = 315 ) square inches. Substituting for ( h ), we have ( w(w + 6) = 315 ). Solving this gives the width ( w \approx 15 ) inches and height ( h \approx 21 ) inches.
What is the area of a triangular prism if the height is W inches the length W inches and the base W inches?
The answer depends on what sort of triangle: right angled, equilateral, isosceles or scalene.
What is the perimeter of a rectangle whose length is 2.5 greater than its width with an area of 37.5 square inches show work?
Suppose width = W inches. Then length, L = W + 2.5 inches. Area = L*W = (W + 2.5)*W which is 37.5 sq inches. Therefore W2 + 2.5W - 37.5 = 0 Multiplying by 2, to get rid of the fraction, 2W2 + 5W - 75 = 0 (2W +15)(W - 5) = 0 So W = -73.5 or W = 5 Since W is a length, it cannot be negative, so W = 5 inches Then L = W + 2.5 = 7.5 inches Therefore, the perimeter is 2*(L+W) = 2*(7.5 + 5) = 2*12.5 = 25 inches.
What is the height of a 6 inches wide 4 inches long prism if the surface area is 308 square inches?
Total surface area = 2*(H*L + L*W + W*H) 308 = 2*(6*4 + 4*W + W*6) that is 154 = 24 + 4W + 6W or 130 = 10 W so that W = 13 inches.
What are the dimensions of a rectangle with a perimeter of 30 inches and an area of 54 square inches?
Let the length be ( l ) and the width be ( w ). The perimeter is given by the formula ( P = 2(l + w) ), so ( l + w = 15 ). The area is given by ( A = l \times w = 54 ). Solving these equations, we find the dimensions are ( l = 18 ) inches and ( w = 3 ) inches.
If the area of a rectangle is 40 square inches and the length is 6 inches more than the width what is the length and the width of the rectangle?
(6 + w) = length w = width (6 + w)(w) = 40 square inches w squared + 6w = 40 w = 4 inches and the length must be equal to 10 inches
The perimeter of a rectangle is 236 inches The length exceeds the width by 64 inches What is the length and width?
P = 2(L + W) = 236 L + W = 118 W + 64 + W = 118 (since L = W + 64) 2W = 54 W = 27 inches and then L = W + 64 = 91 inches
The perimeter of a rectangle is 32 inches Its length is 10 inches What is its width?
32 = L + W + L + W 32 = 10 + W + 10 + W 12 = W + W 6 = W
What is the area of a triangular prism if the height is W inches the length W inches and the base W inches?
The answer depends on what sort of triangle: right angled, equilateral, isosceles or scalene.
What are the dimensions of 800 square inches and under L x W equals IN 2?
There are infinitely many options. Let L ≥ 28.2843 [= sqrt(800] inches. and let W = 800/L inches. Then L=W = L * (800/L) = 800 sq inches. Since L can have by 28.2843 in or ANY larger value, there are infinitely many possibilities. And each one of them gives a valid solution.
What is the perimeter of a rectangle whose length is 2.5 greater than its width with an area of 37.5 square inches show work?
Suppose width = W inches. Then length, L = W + 2.5 inches. Area = L*W = (W + 2.5)*W which is 37.5 sq inches. Therefore W2 + 2.5W - 37.5 = 0 Multiplying by 2, to get rid of the fraction, 2W2 + 5W - 75 = 0 (2W +15)(W - 5) = 0 So W = -73.5 or W = 5 Since W is a length, it cannot be negative, so W = 5 inches Then L = W + 2.5 = 7.5 inches Therefore, the perimeter is 2*(L+W) = 2*(7.5 + 5) = 2*12.5 = 25 inches.
What is the height of a 6 inches wide 4 inches long prism if the surface area is 308 square inches?
Total surface area = 2*(H*L + L*W + W*H) 308 = 2*(6*4 + 4*W + W*6) that is 154 = 24 + 4W + 6W or 130 = 10 W so that W = 13 inches.
A magazine is 11 inches long and 8 inches wide what is the magazine's perimeter?
38 inches = perimeter 2*(w+l); 88 sq inches = Area (w*l)
The length in inches of a box is 3 inches less than twice its width in inches. Find the answer that gives the length l inches in terms of the width w inches of the box?
l = 2*w - 3
What size in inches is a Fat Quarter?
Approximately 18 inches by 22 inches.
What are the dimensions of a rectangle with a perimeter of 30 inches and an area of 54 square inches?
Let the length be ( l ) and the width be ( w ). The perimeter is given by the formula ( P = 2(l + w) ), so ( l + w = 15 ). The area is given by ( A = l \times w = 54 ). Solving these equations, we find the dimensions are ( l = 18 ) inches and ( w = 3 ) inches.
How do you find total inches using L x W x H?
If you multiply L x W x H for a rectangular block if L, W, and H are in inches, you get a volume, in cubic inches, or in3.
