There are 100 integers between 1,234 and 2,345 that are divisible by 11.
Of the 729 numbers that satisfy the requirement of positive integers, 104 are divisible by 7.
(7*100*101)/2 = 35,350 jpacs * * * * * What? How can there be 35,350 integers in the first 100 integers? There are 14 of them.
Divisible by both? 2 numbers... 45 and 90
All numbers from 1 to 100 which are whole numbers are integers
Between 100 and 999 there are 448.
There are 128 integers between 100 and 1000 that are divisible by seven.
There are 100 integers between 1,234 and 2,345 that are divisible by 11.
The total number of integers between 100 and 300 that are divisible by three is 66.
128 of them.
Of the 729 numbers that satisfy the requirement of positive integers, 104 are divisible by 7.
(7*100*101)/2 = 35,350 jpacs * * * * * What? How can there be 35,350 integers in the first 100 integers? There are 14 of them.
There are (500-100)/2 = 200 numbers divisible by 2 between 100 and 500 counting 100 but not 500. Of these (500-100)/8 = 50 are divisible by 8. So there are 150 numbers between 100 and 500 divisible by two but not by 8. By relative primeness exactly 50 out of these 150 are divisible by 3 and therefore these 50 are exactly the ones divisible by 6 but not by 8.
8 of them.
There are 22 such numbers.
you can say that 2/10 of every 10 integers is divisible by 5, so multiplying 2/10 by 100, giving you 200/1000 total integers are divisible by 5. half of all integers are odd, so divide 200/1000 by 2 is 100/1000, so you can correctly state that 100 odd integers under 1000 are divisible by 5.
Divisible by both? 2 numbers... 45 and 90