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To find how many integers from 1 to 1000 have none of their digits repeated, we can analyze the problem by considering the number of digits in the integers. For 1-digit numbers (1-9), there are 9 options. For 2-digit numbers (10-99), the first digit can be chosen in 9 ways (1-9), and the second digit in 9 ways (0-9 excluding the first digit), giving 9 × 9 = 81 combinations. For 3-digit numbers (100-999), the first digit can be chosen in 9 ways, the second in 9 ways, and the third in 8 ways, resulting in 9 × 9 × 8 = 648 combinations. Adding these, we find the total: 9 + 81 + 648 = 738 integers with non-repeating digits from 1 to 1000.
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How many positive integers less than 1000 are 6 times the sum of their digits?
There is only 1, the number 54.
How many integers with distinct digits are there between 1000 and 9999 such that the absolute value of the difference between the first and the last digit is 1?
952 of them.
How many integers between 1 and 10 are dividends of 1000?
1, 2, 4, 5, 8, and 10, so only 6 digits.
How many integers with distinct digits are there between 1000 and 9999 such that the absolute value of the difference between the first and the last digit is 3?
An infinite amount
How many 5 digits can be formed with digits 123456 divisible by 4 with digits not repeated?
192 ways
How many integers from 100 to 1000 contain NO repeated digits?
648
How many odd integers between 1000 and 9999 have distinct digits?
There are 120 of them.
How many odd integers between 1000 and 8000 have only non zero digits?
How many
How many positive integers less than 1000 have no odd decimal digits?
52
How many integers are there between 100 and 1000 all of whose digits are odd?
There are 125 of them.
How many numerals between 11 and 999999 contain repeated single digits?
There are 45 integers between 11 and 999999 which consist of only one digit being repeated. There are 831430 integers that contain at least one repeated digit.
How many positive integers less than 1000 have distinct digits?
10*9*8=720
How many integers between 1000-9999 have distinct digits?
9*9*8*7 = 4536
How many positive integers less than 1000 are 6 times the sum of their digits?
There is only 1, the number 54.
How many positive integers less than 1000 are there such that the digits are not strictly increasing order from left to right?
There are 870 such numbers.
How many integers with distinct digits are there between 1000 and 9999 such that the absolute value of the difference between the first and the last digit is 1?
952 of them.
How many integers between 1 and 10 are dividends of 1000?
1, 2, 4, 5, 8, and 10, so only 6 digits.
