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How many calories to heat 10 ml of water from 25 degrees to 35 degrees C?
Wiki User
∙ 13y ago
100
Wiki User
∙ 13y ago
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How many calories are needed to change 1 gram of 100 degrees Celsius boiling water to 100 degrees Celsius steam?
This is the latent heat of vaporisation of water, which at standard pressure, is 539 calories (per gram).
How many calories does it take to heat a 100.0 grams sample of water from 24.5 degrees C to 38.2 degrees C?
38.2C-24.5C = 13.7 C change this requires 13.7 calories per gram or 1370 calories total
How many calories are required to raise the temperature of 105 grams of water from 30.0 degrees C to 70.0 degrees C?
q (amt of heat) = mass * specific heat * temp. differenceThe specific heat of water is 1.00 cal/goC & the temperature difference is 70-30 = 40oCq = (105 grams)*(1.00 cal/goC)*(40oC)= 4,200 calories
How many calories are required to heat 38.2 grams of aluminum from 102 degrees celsius to 275 degrees celsius?
Specific heat for aluminium = 0.214 Heat required = 38.2 x 0.214 x (275 - 102) = 1414.24 calories
How many kWh's does it take to heat water from 0 degrees C to 37 degrees C with proof please?
To raise the temperature of one cc of water requires i calorie of heat . you did not specify the volume.
How many calories does it take to heat a 100.0 g sample of water from 24.5 degrees to 38.2 degrees?
1370 calories
How many calories are needed to change 1 gram of 100 degrees Celsius boiling water to 100 degrees Celsius steam?
This is the latent heat of vaporisation of water, which at standard pressure, is 539 calories (per gram).
How many calories are needed to heat up 5 grams of water by 3 degrees Celsius?
(5)(3)= 15 calories. 1 calorie is the energy (heat) to raise 1 gram of water by 1 degree celsius, so 5 grams of water (3 degrees Celsius) = 15.
How many calories does it take to heat a 100.0 grams sample of water from 24.5 degrees C to 38.2 degrees C?
38.2C-24.5C = 13.7 C change this requires 13.7 calories per gram or 1370 calories total
How many calories of heat would it take to raise the temperature of 256 grams of water from 20 degrees to 99 degrees?
A calorie is the amount of heat you need to raise the temperature of one gram of water by one degree Celsius. Assuming you are raising the temperature of the water from twenty degrees Celsius to ninety-nine degrees Celsius, it would take 20,000 calories. To calculate this, subtract 20 from 99. This is the amount of degrees you need to raise the temperature of the water by. Then multiply that number by 256, the amount of water in grams. You should get 20,244 calories. In significant digits, your answer should be 20,000 calories.
How many calories are required to raise the temperature of 105 grams of water from 30.0 degrees C to 70.0 degrees C?
q (amt of heat) = mass * specific heat * temp. differenceThe specific heat of water is 1.00 cal/goC & the temperature difference is 70-30 = 40oCq = (105 grams)*(1.00 cal/goC)*(40oC)= 4,200 calories
How many calories are required to heat 38.2 grams of aluminum from 102 degrees celsius to 275 degrees celsius?
Specific heat for aluminium = 0.214 Heat required = 38.2 x 0.214 x (275 - 102) = 1414.24 calories
How many calories of heat is available when a hot water bottle containing 750g of water at 65 degrees cools to body temperature?
To calculate the calories of heat available when the water cools to body temperature, you need to consider the specific heat capacity of water. The specific heat capacity of water is 4.18 J/g°C. By using the formula Q = mcΔT, where Q is the heat energy, m is the mass, c is the specific heat capacity, and ΔT is the temperature change, you can find the answer.
How many calories are required to heat 37.4g of lead from 15 to 60 degrees Celsius?
This heat is 51, 33 cal.
If you have a 2 liter bottle of liquid water at 0 Celsius. About how many Calories are needed to heat up the water to 100 C?
It takes 1 calorie to heat 1 gram of water by 1 degree Celsius. A 2 liter bottle of water weighs around 2000 grams. Therefore, you would need 200,000 calories to heat the water from 0 to 100 degrees Celsius.
How many calories does it take to heat 10 grams of ice to 78 degrees C?
First, you need to melt the ice. Look up the heat of fusion of ice, and multiply that by the amount of grams.Then you need to heat the water, from zero degrees to 78 degrees. Look up the specific heat of water, and then multiply together all of the following: The specific heat; the mass; the temperature difference. Finally, add the two together.
How many calories of heat energy are required to melt 10 grams of ice at 0 degrees celciaus?
The heat energy required to melt ice at 0 degrees Celsius is called the heat of fusion. For ice, the heat of fusion is approximately 334 J/g. To convert this to calories, divide by 4.184 J/cal, which gives you approximately 80 calories of heat energy needed to melt 10 grams of ice.
