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The idea here is to:

* Look up the specific heat of water.

* Multiply the mass, times the temperature difference, times the specific heat of water.

You may need to do some unit conversions first; specifically, if the specific heat is given per kilogram, you can convert the grams to kilograms.

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Q: How much heat is necessary to change 30 grams of water at 40 degrees celsius into water at 60 degrees celsius?
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How much heat is necessary to change a 52.0 gram sample of water at 33.0 degrees Celsius into steam at 110 degrees celsius?

Raise the temp of 52 grams of water from 33.0 C to 100 C = 52*67*4.184 = 14.577 kJConvert evaporate 52 g of water to steam without change of temp = 52*2259 = 117.468 kJRaise the temp of 52 grams of steam from 100 C to 110 C = 52*10*2.02 = 1.051 kJTotal energy required = 133.095 kJ = 31,811 calories or 31.811 kCal.


How much heat is required to raise the temperature to 5.0 mL of water from 2.50 degrees Celsius to 75 degrees Celsius?

Density = grams/ml 1.00 g/ml = X g/5.0 ml = 5.0 grams water ============== q(joules) = mass * specific heat * change in temp. q = (5.0 grams)(4.180 J/gC)(75 C - 2.50 C) = 1515.25 Joules ---------------------------------/4.184 = 362 calories -------------------


How many calories are required to heat 38.2 grams of aluminum from 102 degrees celsius to 275 degrees celsius?

Specific heat for aluminium = 0.214 Heat required = 38.2 x 0.214 x (275 - 102) = 1414.24 calories


How much heat energy will be required to lower the temperature of 2.67kg of steam from 282 degrees Celsius to 105 degrees Celsius?

You mean how much heat energy will be lost/transferred as you are losing Joules here. All in steam, so a simple q problem and no change of state. 2.67 kg = 2670 grams q = (2670 grams steam)(2.0 J/gC)(105 C - 282 C) = - 9.45 X 105 Joules ----------------------------------- This much heat energy must be lost to lower the temperature of the steam.


How much heat is required to vaporize 10 pound ice?

If the ice starts at 0 degrees Celsius and vaporization takes place at 100 degrees Celsius, then ... 10 lbs = 4540 grams Q = 80(4540) + 1(100 - 0)(4540) + 540(4540) Q = 720(4540) = 3,268,800 calories

Related questions

What is the solubility of ammonium chloride at 60 degrees Celsius?

The solubility of ammonium chloride at 60 degrees Celsius is approximately 39.2 grams per 100 grams of water.


What is the solubilty of potassium chloride at 25 degrees Celsius?

The solubility of potassium chloride at 25 degrees Celsius is approximately 34 grams per 100 grams of water.


What would be the final temperature when 250 grams of water at 100 degrees celsius is mixed with 525 grams of water at 30 degrees celsius?

The final temperature would be approximately 54.2 degrees Celsius. This can be calculated using the principle of conservation of energy, where the heat lost by the hot water is equal to the heat gained by the cold water.


What is the density of sulfur at twenty five degrees Celsius?

The density of sulfur at 25 degrees Celsius is approximately 2 grams per cubic centimeter.


How many calories are needed to convert 12.5 grams of ice at 0 degrees Celsius to steam at 100 degrees Celsius?

To convert 12.5 grams of ice at 0 degrees Celsius to steam at 100 degrees Celsius, you would need to provide heat energy for three main processes: heating the ice from 0 degrees Celsius to 100 degrees Celsius, melting the ice into water at 0 degrees Celsius, and then heating the water from 0 degrees Celsius to steam at 100 degrees Celsius. The total calorie requirement would be determined by the specific heat capacities and heat of fusion and vaporization of water.


What is the density of helium at 25 degrees celsius?

The density of helium gas at 25 degrees Celsius is approximately 0.1785 grams per liter.


How many grams of sodium chloride can be dissolved in 100 grams of water at 95 celsius?

Approximately 39 grams of sodium chloride can be dissolved in 100 grams of water at 95 degrees Celsius.


What is the density of 1- propanol at 25 degrees Celsius?

The density of 1-propanol at 25 degrees Celsius is approximately 0.804 g/cm3.


What is the density of warm water cold water and ice?

Density of ice at 0 degrees Celsius is 916.8 grams per cubic centimeter or milliliter. The density of fresh water is dependant on the temperature: At 3.98 degrees Celsius the density is 0.999975 grams per milliliter. At 100 degrees Celsius the density is 0.958.35 grams per milliliter.


How many grams of KCl remain in solution at 20 degrees celsius when a solution containing 80g of KCl in 200g of water at 50 degrees Celsius is cooled to 20 degrees Celsius?

To find the amount of KCl that remains in solution at 20 degrees Celsius, you can use the principle of solubility. Calculate the maximum amount of KCl that can dissolve in 200g of water at 20 degrees Celsius using a solubility chart. Once you have this value, compare it to the initial 80g of KCl to determine how much remains in solution after cooling.


What is the total heat loss if you have 18 grams of aluminum and the temperature changes from 64 degrees Celsius to 48 degrees Celsius?

Approx 4974 Joules.


What is the density of oxygen at 25 degrees Celsius?

The density of oxygen at 25 degrees Celsius is approximately 1.1839 grams per liter (g/L).