Sortega17
The idea here is to:
* Look up the specific heat of water.
* Multiply the mass, times the temperature difference, times the specific heat of water.
You may need to do some unit conversions first; specifically, if the specific heat is given per kilogram, you can convert the grams to kilograms.
Wiki User
∙ 9y agoRaise the temp of 52 grams of water from 33.0 C to 100 C = 52*67*4.184 = 14.577 kJConvert evaporate 52 g of water to steam without change of temp = 52*2259 = 117.468 kJRaise the temp of 52 grams of steam from 100 C to 110 C = 52*10*2.02 = 1.051 kJTotal energy required = 133.095 kJ = 31,811 calories or 31.811 kCal.
Density = grams/ml 1.00 g/ml = X g/5.0 ml = 5.0 grams water ============== q(joules) = mass * specific heat * change in temp. q = (5.0 grams)(4.180 J/gC)(75 C - 2.50 C) = 1515.25 Joules ---------------------------------/4.184 = 362 calories -------------------
Specific heat for aluminium = 0.214 Heat required = 38.2 x 0.214 x (275 - 102) = 1414.24 calories
You mean how much heat energy will be lost/transferred as you are losing Joules here. All in steam, so a simple q problem and no change of state. 2.67 kg = 2670 grams q = (2670 grams steam)(2.0 J/gC)(105 C - 282 C) = - 9.45 X 105 Joules ----------------------------------- This much heat energy must be lost to lower the temperature of the steam.
If the ice starts at 0 degrees Celsius and vaporization takes place at 100 degrees Celsius, then ... 10 lbs = 4540 grams Q = 80(4540) + 1(100 - 0)(4540) + 540(4540) Q = 720(4540) = 3,268,800 calories
The solubility of ammonium chloride at 60 degrees Celsius is approximately 39.2 grams per 100 grams of water.
The solubility of potassium chloride at 25 degrees Celsius is approximately 34 grams per 100 grams of water.
The final temperature would be approximately 54.2 degrees Celsius. This can be calculated using the principle of conservation of energy, where the heat lost by the hot water is equal to the heat gained by the cold water.
The density of sulfur at 25 degrees Celsius is approximately 2 grams per cubic centimeter.
To convert 12.5 grams of ice at 0 degrees Celsius to steam at 100 degrees Celsius, you would need to provide heat energy for three main processes: heating the ice from 0 degrees Celsius to 100 degrees Celsius, melting the ice into water at 0 degrees Celsius, and then heating the water from 0 degrees Celsius to steam at 100 degrees Celsius. The total calorie requirement would be determined by the specific heat capacities and heat of fusion and vaporization of water.
The density of helium gas at 25 degrees Celsius is approximately 0.1785 grams per liter.
Approximately 39 grams of sodium chloride can be dissolved in 100 grams of water at 95 degrees Celsius.
The density of 1-propanol at 25 degrees Celsius is approximately 0.804 g/cm3.
Density of ice at 0 degrees Celsius is 916.8 grams per cubic centimeter or milliliter. The density of fresh water is dependant on the temperature: At 3.98 degrees Celsius the density is 0.999975 grams per milliliter. At 100 degrees Celsius the density is 0.958.35 grams per milliliter.
To find the amount of KCl that remains in solution at 20 degrees Celsius, you can use the principle of solubility. Calculate the maximum amount of KCl that can dissolve in 200g of water at 20 degrees Celsius using a solubility chart. Once you have this value, compare it to the initial 80g of KCl to determine how much remains in solution after cooling.
Approx 4974 Joules.
The density of oxygen at 25 degrees Celsius is approximately 1.1839 grams per liter (g/L).