The question is not sufficiently specified: the answer will depend on what you are asking about.
How much generated?
How much used?
In which country/region?
Usage by individual/household/per head of population in a region?
To calculate the 30-day cost with a rate of 13.1 cents per kilowatt-hour (kWh), you need to know the total energy consumption in kWh over that period. Multiply the total kWh used by 0.131 (which is 13.1 cents converted to dollars) to get the total cost. For example, if you used 1000 kWh in a month, the cost would be 1000 kWh × 0.131 = $131.
0.6726
1 Mwh = 1000 Kwr
New energy star models are about 470 kWh per year.
KWH
100 kWh
You better have a 10,000 watt capable generator.
1 MWh is equal to 1,000 kWh.
A 100 W light uses a power of 0.1 kW all the time it's switched on, which means it uses 0.1 kWh each hour. So it uses 1 kWh in ten hours. In a month of 30 days totalling 720 hours, it would use 72 kWh of energy.
At 10 cents per kWh (Kilowatt hour), one 100 watt incandescent light bulb ran for 24 hours straight will cost 24 cents a day. $7.30 a month, $87.60 a year. kWh = (Watts Used * Hours per Day * Days per Month) / 1000 Cost per Month = kWh * Cost per kWh
I have a 2800sf home and a pool, I live in North Texas. During the summer its about 3000 kwh or $300 to $400 a month. During the winter its about 1500 kwh or $150 to $200 a month.
1 kWh is equal to 3.6 million joules.
approximately 40 kWh
A 1 megawatt plant can produce 720,000 kilowatt-hours (kWh) per month if operating at full capacity for 30 days. This is calculated by multiplying the plant's capacity (1 megawatt) by the number of hours in a month (720 hours) to get the total kilowatt-hours produced.
There are 277.778 kilowatt-hours (kWh) in one petajoule (PJ).
Dinorwig is a 'pumped storage' hydro power facility. It has a capacity to produce 1.89GW of electricity, which equates to 6.8TWh. I terms of kWh, this would be 6.8E9 kWh or 6,800,000,000 kWh. (6.8 billion kWh).
To calculate the cost per month for the appliance, you first need to find the power consumption in kilowatts per hour (kWh). For a 110V appliance drawing 12A, the power consumption would be 1.32 kW (110V * 12A = 1320W = 1.32 kW). Multiply this by the number of hours the appliance runs per month to get the total kilowatt-hours (kWh) used, then multiply by the cost per kWh. If the appliance runs for, say, 100 hours a month, the calculation would be: 1.32 kW * 100 hours = 132 kWh * $0.09 = $11.88 per month.