one BTU is approximately the amount of energy needed to heat 1 pound of water 1 degree Fahrenheit. Here is a start ; now find out how much a pound of water weighs then work through it.
Degrees Fahrenheit are a unit of temperature and British Thermal Units are units of heat; in physics, temperature and heat are not the same thing (although they are synonymous in normal English usage). To explain, the heat content of an object depends upon both the temperature and the heat capacity of that object, so for example, one liter of water has only half the heat capacity of two liters of water; even if your one liter container is at exactly the same temperature as the two liter container, it still has only half the heat content as measured in BTUs. So, since these units do not measure the same thing, they cannot be converted into eachother.
Heat required = (mass) x (specific heat of substance) x (temp difference) In this case it would be (100) x (1) x (50-20) = 100 x 30 = 3000 cals
Heat required for this transition is given as the the sum of three heatsheat required for heating the ice from -5 degree Celsius +latent heat(conversion of ice at zero degree to water at zero degrees)+heat required to heat the water from 0 to 5 degree CelsiusHeating of ice=m x s x delta T,where m is the mass ,s is the specific heat of ice=200x0.5x5=500calmelting of ice=mxlatent heat=200x80=16,000calHeating of water=m x s x delta T,where m is the mass ,s is the specific heat of water =200x1x5=1000calTotal heat required=500+16,000+1000=17,500 cal
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It takes 1000 calories to heat 1 litre of water 1 degree C.
It takes about 4.18 Joules of energy to heat 1 gram of water by 1 degree Celsius. Therefore, to heat 1 liter (1000 grams) of water by 1 degree Celsius, it would require about 4180 Joules. Converting this to watts depends on the time taken to heat the water.
The amount of heat needed to raise the temperature of 1 kilogram of water by 1 degree Celsius is 4186 Joules, which is the specific heat capacity of water.
It takes 1 calorie to heat 1 gram of water by 1 degree Celsius. A 2 liter bottle of water weighs around 2000 grams. Therefore, you would need 200,000 calories to heat the water from 0 to 100 degrees Celsius.
To achieve 49 degrees in the 20-liter tank, you will need to calculate the energy required to heat the cold water to 80 degrees. Then, calculate the heat exchange between the hot and cold water to reach the final temperature of 49 degrees. The amount of 80-degree water needed depends on the specific heat capacity of both hot and cold water.
Yes, one calorie is the amount of heat needed to raise the temperature of 1 kilogram of water 1 degree Celsius.
Calor is a latin prefix meaning heat. A Calorie is actually a unit of energy based on the energy needed to raise one liter of water one celsius degree
The specific heat of water is 4.179 Joules per gram per degree Centigrade. The density of water is 1 gram per cubic centimeter, so one liter is 1000 grams. This means it takes 4179 Joules to raise one liter one degree Centigrade.
The calorific value of water is 80cal/degree. so it takes 60*80=2400cal of heat.
One calorie is needed to heat 1 gram of water 1 degree Celsius
This is one calorie
200000 calories. 1 gm of water needs 1 cal(calorie) to raise it's temperature through 10C. Now, density of water = 1gm/ml at 40C and we assume that it's density is same at 00C. So we have 2000gm of water. For raising temp by 10C we need 2000 cal. For raising temp by 1000C we need 2000 x 100 cal = 200000 calories