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How many btu stored in 1 gal of 120 degree water?
one BTU is approximately the amount of energy needed to heat 1 pound of water 1 degree Fahrenheit. Here is a start ; now find out how much a pound of water weighs then work through it.
Convert degree of Fahrenheit to btu?
Degrees Fahrenheit are a unit of temperature and British Thermal Units are units of heat; in physics, temperature and heat are not the same thing (although they are synonymous in normal English usage). To explain, the heat content of an object depends upon both the temperature and the heat capacity of that object, so for example, one liter of water has only half the heat capacity of two liters of water; even if your one liter container is at exactly the same temperature as the two liter container, it still has only half the heat content as measured in BTUs. So, since these units do not measure the same thing, they cannot be converted into eachother.
How many btu's to heat 1 POUND OF water 1 degree?
To heat 1 pound of water by 1 degree Fahrenheit, you need 1 British Thermal Unit (BTU). This is based on the definition of a BTU, which is the amount of heat required to raise the temperature of one pound of water by one degree Fahrenheit at a constant pressure.
How many calories are needed to raise the temp of 100 grams of water from 20 degree C to 50 degree C?
Heat required = (mass) x (specific heat of substance) x (temp difference) In this case it would be (100) x (1) x (50-20) = 100 x 30 = 3000 cals
How much heat is required to change 0.2kg of ice at -5 degrees to water at 5 degrees?
Heat required for this transition is given as the the sum of three heatsheat required for heating the ice from -5 degree Celsius +latent heat(conversion of ice at zero degree to water at zero degrees)+heat required to heat the water from 0 to 5 degree CelsiusHeating of ice=m x s x delta T,where m is the mass ,s is the specific heat of ice=200x0.5x5=500calmelting of ice=mxlatent heat=200x80=16,000calHeating of water=m x s x delta T,where m is the mass ,s is the specific heat of water =200x1x5=1000calTotal heat required=500+16,000+1000=17,500 cal
