212 - 80 = 132 degrees temperature increase x 1 pound water = 132 BTU
You would need to remove approximately 1200 BTUs of heat to convert a gallon of water to ice. There are 8.34 lb in a gallon of water, which converting to lb-moles is 0.463. The latent heat of crystallization for water is -2583.4 BTU/lb-mole. Multiplying the two together and you get -1197 BTUs, which means you need to remove that amount of heat to convert the gallon of water to ice.
one BTU is approximately the amount of energy needed to heat 1 pound of water 1 degree Fahrenheit. Here is a start ; now find out how much a pound of water weighs then work through it.
1 BTU (british thermal unit) of heat energy will change the temperature of 1 pound of water by 1 degree Fahrenheit. If you are talking about 1 pound of water, since this is a change of 100 deg f, it would require 100 BTU. 2 pounds require 200 BTU. 3 pounds require 300 BTU. etc.
Heat required for this transition is given as the the sum of three heatsheat required for heating the ice from -5 degree Celsius +latent heat(conversion of ice at zero degree to water at zero degrees)+heat required to heat the water from 0 to 5 degree CelsiusHeating of ice=m x s x delta T,where m is the mass ,s is the specific heat of ice=200x0.5x5=500calmelting of ice=mxlatent heat=200x80=16,000calHeating of water=m x s x delta T,where m is the mass ,s is the specific heat of water =200x1x5=1000calTotal heat required=500+16,000+1000=17,500 cal
To raise the temperature of 1 pound of water by 1 degree Fahrenheit, it requires 1 BTU (British Thermal Unit). Therefore, to heat water by 10 degrees, it would require 10 BTUs per pound of water. This value may vary slightly depending on the specific heat capacity of the water.
212 - 80 = 132 degrees temperature increase x 1 pound water = 132 BTU
One BTU (British Thermal Unit) is required to reduce one pound of water by one degree Fahrenheit. The amount of BTUs needed to reduce the temperature of a specific amount of water by one degree will depend on the weight of the water being heated.
One measure does not directly translate to another. A BTU is the amount of heat that it takes to raise the temp of one pound of water by one degree F. A burning match, and a burning fireplace may both be at 650 degrees, but the fireplace gives off more heat (more BTUs)
It takes approximately 970 BTUs to vaporize one pound of water. Therefore, for 5 pounds of water, it would require 4850 BTUs to vaporize all of it.
There are no BTUs in an office water-cooler. But you can calculate how many BTUs are removed by the cooler. One BTU or British Thermal Unit is the amount of heat energy required to raise the temperature of one pound of water one degree Fahrenheit. There for when you remove one BTU you are lowering one pound of water one degree Fahrenheit. So if you know how many pounds of water you have and the temperature of the water you start with and the temperature of the water comming out of the cooler you can calculate how many BTUs the cooling unit of the water cooler has removed. BTU=Temp1 - Temp 2 X LB water
BTUs, or British Thermal Units, measure the amount of heat energy required to raise the temperature of one pound of water by one degree Fahrenheit. The formula to calculate BTUs is: BTUs = weight of water (in pounds) x temperature change (in degrees Fahrenheit) x 1. Alternatively, the formula can be expressed as: BTUs = (Flow rate in gallons per minute x change in temperature in degrees Fahrenheit) / 500.
LATENT HEAT OF FUSION When one pound of ice melts, it absorbs 144 BTUs at a constant temperature of 32°F. If one pound of water is to be frozen into ice, 144 BTUs must be removed from the water at a constant temperature of 32°F.
1)This is a 5 part question. The first is realizing that 20F to 32F uses .5BTU per pound per degree. That means it takes 32-20=12*.5=6BTUs to get the ice to 32F. 2)Then you need to know the Latent Heat of Fusion for Ice which is 144BTUs (given). Lets assumes the ice changes from ice to water instantaneously at 32F. 3)Next we calculate the BTUs from 32F to 212F. Which is 1BTU per pound per degree F. 212-32=180 so it take 180BTUS. 4)Next we have to use the Latent Heat of Vaporization of water which will say instantaneously converts water to vapor. This takes 970BTUS (given). 5)Then we calculate the BTUS from 212F to 220F. Which is .5BTUs per pound per degree F which is 220-212=8*.5=4BTUs...... Finally add up all the BTUs and you get 6+144+180+970+4=1304BTUs.
To change 10 pounds of ice at 20 degrees Fahrenheit to steam at 220 degrees Fahrenheit, you need to supply enough energy to first melt the ice, then heat the water to the boiling point, and finally convert it to steam. This process requires approximately 180 BTUs per pound of ice to melt it, 180 BTUs per pound of water to heat it to the boiling point, and then 970 BTUs per pound of water to convert it to steam. So, for 10 pounds of ice, the total BTUs required would be around 18,300 BTUs.
1)This is a 5 part question. The first is realizing that 20F to 32F uses .5BTU per pound per degree. That means it takes 32-20=12*.5=6BTUs to get the ice to 32F. 2)Then you need to know the Latent Heat of Fusion for Ice which is 144BTUs (given). Lets assumes the ice changes from ice to water instantaneously at 32F. 3)Next we calculate the BTUs from 32F to 212F. Which is 1BTU per pound per degree F. 212-32=180 so it take 180BTUS. 4)Next we have to use the Latent Heat of Vaporization of water which will say instantaneously converts water to vapor. This takes 970BTUS (given). 5)Then we calculate the BTUS from 212F to 220F. Which is .5BTUs per pound per degree F which is 220-212=8*.5=4BTUs...... Finally add up all the BTUs and you get 6+144+180+970+4=1304BTUs.
A 100 pound propane tank can produce around 2,160,000 BTUs (British Thermal Units) of heat energy. This can vary slightly based on the quality of the propane and efficiency of the appliance using it.